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2 years ago

A printer can print 12 pages in 9 seconds. What is the closest estimate of the

Mathematics

2 answers:

vivado [14]2 years ago

8 0

Answer:

Step-by-step explanation:

12/9 is the amount of pages it can print in one second, which equals 1 1/3.

multiply that number by 60 (60 seconds in a minute) and there is your answer.

kolbaska11 [484]2 years ago

7 0

Answer:

Step-by-step explanation:

there are 60 seconds in a minute so about 6 9 seconds in a minute. then there is 12 pages per 9 seconds and since there is 6 9 seconds then you can just multiply 6 by 9 to get the answer 72

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In this fraction, which number is the denominator? 1/15 A. 1 B. 15

sweet [91]

Answer: B. 15

Step-by-step explanation: The number on the bottom of the fraction is always the denominator, therefore 15 is the denominator in the fraction.

3 0

3 years ago

SYSTEM OF EQUATION WITH SUBSTITUTION

-BARSIC- [3]

Answer:

Step-by-step explanation:

X=7

Y=0

8 0

3 years ago

Read 2 more answers

. If 3n + 8 = 44, what is the value of n?

algol13

Answer:

3n + 8 = 44

Subtract both sides by 8.

3n = 36

Divide both sides by 3.

n = 12.

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3 years ago

Read 2 more answers

Pls help i need it!!!

Stels [109]

Answer:

there were rivalries between African leaders.

Step-by-step explanation:

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2 years ago

Use the table of integrals, or a computer or calculator with symbolic integration capabilities, to find the indefinite integral.

andriy [413]

Answer:

$\frac{2}{3}(\frac{1}{5}ln|3x-5|-\frac{1}{5}ln|x|)+C$

Step-by-step explanation:

We have been given a indefinite integral $\int \frac{2}{3x\left(3x-5\right)}dx$ . We are asked to find the indefinite integral.

We will use partial fraction formula to solve our given problem.

$\frac{2}{3x\left(3x-5\right)}=\frac{3}{5(3x-5)}-\frac{1}{5x}$

$\int \frac{2}{3x\left(3x-5\right)}dx=\frac{2}{3}\int \frac{1}{x\left(3x-5\right)}dx$

$\frac{2}{3}\int \frac{1}{x\left(3x-5\right)}dx=\frac{2}{3}\int \frac{3}{5(3x-5)}-\frac{1}{5x}dx$

Using difference rule of integrals, we will get:

$\frac{2}{3}(\int \frac{3}{5(3x-5)}dx-\int \frac{1}{5x}dx)$

Now, we need to use u-substitution as:

Let $u=3x-5$ .

$\frac{du}{dx}=3$

$dx=\frac{1}{3}du$

$\int \frac{3}{5(3x-5)}dx= \frac{3}{5}\int \frac{1}{(u)}*\frac{1}{3}du=\frac{3}{5}*\frac{1}{3}\int \frac{1}{(u)}du=\frac{1}{5}ln|u|=\frac{1}{5}ln|3x-5|$

$\int \frac{1}{5x}dx=\frac{1}{5}\int \frac{1}{x}dx=\frac{1}{5}ln|x|$

Substitute back these values:

$\frac{2}{3}(\int \frac{3}{5(3x-5)}dx-\int \frac{1}{5x}dx)=\frac{2}{3}(\frac{1}{5}ln|3x-5|-\frac{1}{5}ln|x|)$

Let us add a constant C.

$\frac{2}{3}(\frac{1}{5}ln|3x-5|-\frac{1}{5}ln|x|)+C$

Therefore, our required integral would be $\frac{2}{3}(\frac{1}{5}ln|3x-5|-\frac{1}{5}ln|x|)+C$ .

5 0

3 years ago