the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
Answer:
(7×x)+14
Step-by-step explanation: Because we have 14 added to something, we will need a + to whatever we are adding to. The product of 7 and a number is 7×x because product is the number you get after multiplication. So we get 7×x+14. You dont need parenthesis
Hope this helps!
Answer: The value of
is
.
Step-by-step explanation:
Given: 
To find: 
As we know it is composition function which means that g(x) function is in f(x) function.
So we have
![(f_\circ g) (x) = f[g(x)]](https://tex.z-dn.net/?f=%28f_%5Ccirc%20g%29%20%28x%29%20%3D%20%20f%5Bg%28x%29%5D)

Now substitute the value of g(x) we get

Hence, the value of
is
.
Answer:
A. false
B. true
C. true
D. false
step-by-step:
A: probability of spinning a 4 on spinner A is 1/4 and probability of spinning a 4 on spinner B is 1/3.
B: there are 2 fours out of 6 possible options so that makes it 2/6, simplify that, it becomes 1/3.
C: 2 and 4 are even numbers so that makes 2/4 possible on spinner A. simplify 2/4 and that becomes 1/2.
D. spinning a 3 on spinner A would make it 1/4 (already simplified). spinning a 3 on spinner B would make it 1/6 (already simplified) therefore spinner A is greater.
Answer:
Either -4n or 0n but most likely -4n