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3 years ago

How to solve a one step equation of R+3= -6 1/2 please show all the work

1 answer:

6 0

Solve for R:
R + 3 = -(1/2 + 6)
Put 1/2 + 6 over the common denominator 2. 1/2 + 6 = (2×6)/2 + 1/2:
R + 3 = -(2×6)/2 + 1/2
2×6 = 12:
R + 3 = -(12/2 + 1/2)
12/2 + 1/2 = (12 + 1)/2:
R + 3 = -(12 + 1)/2
12 + 1 = 13:
R + 3 = -13/2
Subtract 3 from both sides:
R + (3 - 3) = -13/2 - 3
3 - 3 = 0:
R = -13/2 - 3
Put -13/2 - 3 over the common denominator 2. -13/2 - 3 = (-13)/2 + (2 (-3))/2:
R = (-13)/2 - (3×2)/2
2 (-3) = -6:
R = (-6)/2 - 13/2
(-13)/2 - 6/2 = (-13 - 6)/2:
R = (-13 - 6)/2
-13 - 6 = -19:
Answer: R = (-19)/2

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kvv77 [185]

Answer:

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Step-by-step explanation:

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ziro4ka [17]

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1 year ago

The mother of Kriz Anthony was hospitalized and he needs an

Artyom0805 [142]

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Step-by-step explanation:

If the interest is compunded quarterly, then the accumulated amount after t years will be:

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Given: P= 50,000 , r= 5% = 0.05, t= 4 years

Then,

$A=50000(1+\dfrac{0.05}{400})^{4(4)}\\\\= 50000(1+0.000125)^{16}\\\\=50000(1.000125)^{16}\\\\=50000(1.002)\\\\=\$50,100$

Hence, Kriz should pay $50,100 at the end of the term.

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3 years ago

Prove that if one solution for a quadratic equation of the form x 2 + bx + c = 0 is rational (where b and c are rational), then

erica [24]

$x^2+bx+c = (x-r)(x-s)\\
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3 years ago