Pls help I have no clue
1 answer:
Step-by-step explanation:
y-2 = - 3(x-3)
y - 2 =-3x +9
y -2 +2 = - 3x +9 +2
y = - 3x +11
To find the the coordinate
When x =0
y = - 3(0) +11
y= 11
When y = 0
0 = - 3x +11
Subtract 11 from both sides
-3x = - 11
x = 11/3
The y intercept is 11 so, one of your points will be at (0, 11) while the other will be at (11/3, 11).
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Graph the system of linear inequalities
x + y > 5
- x - y < -5
First we graph x + y >5
Step 1: replace > symbol by = sign
x + y =5
step 2 : Solve the equation for y
x + y =5 (subtract x from both sides)
y = 5 - x
step 3: Now we make a table . plug in some number for x and find out y
x -----> y
-1 -----> 6 ( y=5-x => y=5-(-1)= 6)
0 -----> 5 ( y=5-x => y=5-(0)= 5)
1 -----> 4 ( y=5-x => y=5-(1)= 4)
Step 4: we graph the table.
step 5: Shade the region that satisfies our inequality
x + y > 5. Greater than symbol implies that we shade the graph to the right
Graphing second inequality - x - y < -5
All terms have negative sign . so divide all the terms by -1. When we divide an inequality by -1 its sign changes
- x - y < -5 becomes x + y > 5
Follow the same steps to graph this inequality
After dividing the second equation by -1 , we got the same as the first equation.
So we will get the same graph
Both graphs overlaps
The graph of first and second inequality overlaps
The graph is attached below
