The equation of a straight line is y=mx+b, where m is the slope of the line.
By substituting the given information into this equation, we get:
7=(2/3×1)+b
Now solve to find b, the y intercept:
7=2/3+b
b=19/3
So the equation of the line is y=2/3x+19/3
Answer: f(x) = x/4
Steps:
f(x) = 4x
y = 4x
(Change x and y)
x = 4y
(Solve for y)
x/4 = y
(Change to f(x))
f(x) = x/4
It’s a proportional relationship because all of the points on the graph create a straight line
Answer:
![21d+25\leq 115](https://tex.z-dn.net/?f=21d%2B25%5Cleq%20115)
Max is 4 days.
Step-by-step explanation:
An inequality is a math statement with more the one solution. The solution has a range of values for which the inequality can be satisfied. It has the same following components as an equation: variables and operations. However, the equal sign is replaced by an inequality sign:
.
We start by choosing a variable for an unknown value. Here is it the number of days he rents the car. We choose d.
We know he rents it for $21 pr day or 21d for any number of days. We also know her will drive 250 miles at $0.10 per mile or 0.10(250). We will combine the two into an expression.
21d + 0.10(250)
We know his limit is $115. This means he can rent the car for any number of days until he reaches $115. The charge must be less than or equal to 115.
So we write
.
To find the number of days he can rent the car, we solve for d using inverse operations.
![21d+0.10(250)\leq 115\\21d+25\leq 115\\21d+25-25\leq 115-25\\21d\leq 90\\\frac{21d}{21} \leq \frac{90}{21}\\d\leq 4.3](https://tex.z-dn.net/?f=21d%2B0.10%28250%29%5Cleq%20115%5C%5C21d%2B25%5Cleq%20115%5C%5C21d%2B25-25%5Cleq%20115-25%5C%5C21d%5Cleq%2090%5C%5C%5Cfrac%7B21d%7D%7B21%7D%20%5Cleq%20%5Cfrac%7B90%7D%7B21%7D%5C%5Cd%5Cleq%204.3)
This means Jim can rent the car up to 4 days. The 5th day will put the cost over $115.
Answer:
315
Step-by-step explanation:
Each of the 15 teams plays each of the other 14, for a total of 210 games. However, that count includes both A playing B and B playing A. Hence, if the teams meet 3 times, the total number of games will be 3/2 this amount:
(15)(14)(3/2) = 315 . . . league games