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tester [92]
3 years ago
6

Evaluate the expression below at x = 6.

Mathematics
1 answer:
Natalija [7]3 years ago
3 0

Answer:

B

Step-by-step explanation:

you can break the 78 into 70 and 8, and multiply them separately by 6 and then add the two answers to get 468

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Evaluate the square root to find the rational equivalent.
Iteru [2.4K]

Answer:

JJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJ

Step-by-step explanation:

7 0
3 years ago
The age of United States Presidents on the day of their first inauguration follows a Normal distribution with mean 56 and standa
Talja [164]

Answer:

a) 0.7088 = 70.88% probability that a randomly selected President was less than 60 years old on the day of their first inauguration.

b) The 75th percentile for the age of United States Presidents on the day of inauguration is 61.

c) 0.8643 = 86.43% probability that the average age on the day of their first inauguration for a random sample of 4 United States Presidents exceeds 60 years.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The age of United States Presidents on the day of their first inauguration follows a Normal distribution with mean 56 and standard deviation 7.3.

This means that \mu = 56, \sigma = 7.3

(a) (5 points) Compute the probability that a randomly selected President was less than 60 years old on the day of their first inauguration.

This is the pvalue of Z when X = 60. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 56}{7.3}

Z = 0.55

Z = 0.55 has a pvalue of 0.7088

0.7088 = 70.88% probability that a randomly selected President was less than 60 years old on the day of their first inauguration.

(b) (5 points) Compute the 75th percentile for the age of United States Presidents on the day of inauguration.

This is X when Z has a pvalue of 0.75. So X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 56}{7.3}

X - 56 = 0.675*7.3

X = 61

The 75th percentile for the age of United States Presidents on the day of inauguration is 61.

(c) (5 points) Compute the probability that the average age on the day of their first inauguration for a random sample of 4 United States Presidents exceeds 60 years.

Now, by the Central Limit Theorem, we have that n = 4, s = \frac{7.3}{\sqrt{4}} = 3.65

This is the pvalue of Z when X = 60. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{60 - 56}{3.65}

Z = 1.1

Z = 1.1 has a pvalue of 0.8643

0.8643 = 86.43% probability that the average age on the day of their first inauguration for a random sample of 4 United States Presidents exceeds 60 years.

4 0
3 years ago
To go on a summer trip Manuel borrows $200. He makes no payments until the end of 4 years, when he pays off the entire loan. The
belka [17]

Answer:

A)40

B)240

Step-by-step explanation:

5% of 200 is 10

10*4 year=$40 interest

200+40=240 which is total

Im pretty sure

7 0
3 years ago
Day 1 Michael ran 5 miles day 2 Michael ran 2 miles day 3 Michael ran 7 miles day 4 Michael ran 3 miles how many more miles did
Nuetrik [128]

Answer:

5 And there is extra info.

Step-by-step explanation:

Day 3= 7 miles.

Day 2=2 miles.

7-2= 5

6 0
4 years ago
What is the probability you will $100 in the vent from the last question
Harman [31]
C let me know if I’m wrong
5 0
3 years ago
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