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3 years ago

Evaluate the expression below at x = 6.

Mathematics

1 answer:

Natalija [7]3 years ago

3 0

Answer:

Step-by-step explanation:

you can break the 78 into 70 and 8, and multiply them separately by 6 and then add the two answers to get 468

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What method can you use to find the area of the composite figure? Check all that apply.

olga2289 [7]

Answer:

Decompose the figure into two rectangles and add the areas.

Step-by-step explanation:

We can draw a vertical line segment from the smaller section of the rectangle straight down. This would cut the rectangle into 2 smaller rectangles. We can then find the area of each rectangle and add them to find the area of the composite figure.

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3 years ago

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Find the slope 5x - 2y = 10 M=_______

Eva8 [605]

Answer:

Slope is 5/2

Step-by-step explanation:

5x-2y=10

subtract 5x from both sides

-2y=-5x+10

Then you divide -2 on both sides

y=5/2x-5

Which will result 5/2 as the slope

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3 years ago

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Write the expression as a single logarithm

Yakvenalex [24]

$\log _a(6w+1)^{7} + \log _a(w+7)^{\frac{1}{5}} \\ \log _a(6w+1)^{7} + \log _a\sqrt[5]{(w+7)}\\\log _a((6w+1)^{7} (\sqrt[5]{(w+7)}))$

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3 years ago

(-3+x) divided by 2= negative one half

Arlecino [84]

Answer:

are u trying to find x?

Step-by-step explanation:

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3 years ago

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Determine the equation of the circle graphed below.

sergij07 [2.7K]

Answer:

Equation = (x - 6 )² + ( y + 3 )² = 9

Step-by-step explanation:

The circle passes through ( 6, 0) and ( 6 , -6)

They are the coordinates of the diameter.

Using this we can find the centre of the circle.

Find the centre of the circle.

Centre of the circle is the mid- point of (6, 0) and ( 6, -6)

$Centre = (\frac{x_1+x_2}{2} , \frac{y_1 + y_2}{2})$

$=(\frac{6 + 6}{2}, \frac{0 + (-6)}{2})\\\\=(6, -3)$

Find the radius of the circle.

$Radius = \frac{Diameter }{2}$

Diameter is the distance between the points (6 , 0) and ( 6, - 6)

$Diameter = \sqrt{(x_2 - x_1)^2+ (y_2 - y_1)^2\\}$

$=\sqrt{(6-6)^2 + (-6 -0)^2}\\\\=\sqrt{0 + 36} \\\\= 6$

Therefore,

$Radius ,r = \frac{6}{2} = 3$

Standard equation of a circle:

$(x - a)^2 + (y - b)^2 = r^2 \ where \ (a , b) \ is \ the\ centre \ coordinates.$

Therefore , equation of the circle ;

$(x - 6)^2 + (y + 3)^2 = 3^2\\\\(x -6)^2 + (y + 3)^2 = 9$

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3 years ago