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3 years ago

In a cookie jar,

Mathematics

1 answer:

Sedbober [7]3 years ago

7 0

well, a WHOLE is 1, which we can split in many fractions, say 5/5, 10/10 or 999/999 and so on.

we know 1/5 of the jar is chocolate chip, and there's the rest, well, the Whole jar in 5ths have to be 5/5, if we take away 1/5 from 5/5, the "rest" is 5/5 - 1/5 = 4/5.

now, we also know that 1/2 of the "rest" is peanut butter, or namely that 1/2 of 4/5 is peanut butter, how much will that be? let's divide 4/5 by 2

$\cfrac{4}{5}\div 2\implies \cfrac{4}{5}\div \cfrac{2}{1}\implies \cfrac{4}{5}\cdot \cfrac{1}{2}\implies \cfrac{4}{10}\implies \cfrac{2}{5}$

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Evaluate 1 1/4 x 6 giving your answer as a mixed number in simplest form.

Genrish500 [490]

Answer:

7 1/2

Step-by-step explanation:

First remember the rule to multiply fractions, you gots to have fractions; so convert 1 1/4 into a mixed number. To do this, multiply 1 by 4, then add 1. It equals 5/4.

Next multiply 5/4 by 6. You can "cross simplify" to make this problem easier and you will the the simplest form. To cross simplify, divide 6 and 4 by 2. The new thing is 5/2 times 3. This equals 15/2.

Divide but don't turn into decimal. 7 remainder 1 the divisor is 2.

Put them together 7 1/2

Final answer 7 1/2

Hope this helps

7 0

3 years ago

What is the approximate value of b, rounded to the nearest tenth? Use the law of sines to find the answer. Law of sines: answers

Dominik [7]

Answer:

$\boxed{\text{2. 4.7 units}}$

Step-by-step explanation:

Assume your triangle has the dimensions shown below.

Before we can use the Law of Sines, we must find ∠C.

1. Calculate ∠C

$\begin{array}{rcl}A + B + C & = & 180^{\circ}\\66^{\circ} + 76^{\circ} + C & = & 180^{\circ}\\142^{\circ} + C & = & 180^{\circ}\\C & = & 38\, ^{\circ}\\\end{array}$

2. Calculate b

Use the Law of Sines

$\begin{array}{rcl}\dfrac{b}{\sin B } & = & \dfrac{c}{\sin C}\\\\\dfrac{b}{\sin 76^{\circ}} & = & \dfrac{3}{\sin 38^{\circ}}\\\\\dfrac{b}{0.9703} & = & \dfrac{3}{0.6157}\\\\ & = & 4.873\\b & = & 0.9703\times 4.873\\& = & \boxed{\mathbf{4.7}}\\\end{array}$

7 0

3 years ago

What is the perimeter of ABCD?<br> Perimeter=

swat32

The perimeter is 10 +10+9+9 so its 38

8 0

3 years ago

Read 2 more answers

Two students in your class, Tucker and Karly, are disputing a function. Tucker says that for the function, between x = –3 and x

Effectus [21]

The difference between Tucker and Karly's take is that Tucker's solution is analytical while Karly's is graphical. But both are correct either way.

For Tucker's solution, let's say at x=-3 the value for y is 4, and at x=3, the value of y is still 4, then the average rate of change or slope is 0. Note that the slope of the curve is Δy/Δx. Since there is no change for Δy, the slope is zero.

For Karly's solution, even if the curve travels high or low but would have the same elevation of x=-3 and x=3, the average rate of change is still zero. It is actually just same with Tucker's but Karly just verbalizes her solution that was observed visually.

7 0

3 years ago

A rhombus and a triangle are equal in areas. if the base and height of the triangle are 24.8 cm and 5.5 cm respectively and the

ipn [44]

<h2>Given :-</h2>

Area of Rhombus = Area of Triangle

Base and Height of Triangle is 24.8 cm and 5.5 cm respectively .

Length of one diagonal of the rhombus is 22 cm .

Length of other Diagonal

<h2>Solution :-</h2>

As we know that

Area of triangle = ½ × Base × Height

Area = ½ × 24.8 × 5.5
Area = 1 × 12.4 × 5.5
Area = 12.4 × 5.5
Area = 68.2 cm²

Area of rhombus = ½ × D1 × D2

68.2 = ½ × 22 × D2
68.2 × 2 = 22 × D2
136.4 = 22 × D2
136.4/22 = D2
6.2 = D2
D2=6.2

<h2>Hence :-</h2>

<h3>Other Diagonal is 6.2 cm.</h3>

$\begin{gathered} \\ \end{gathered}$

7 0

3 years ago