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4 years ago

Don has 72 servings of peanut butter and 40 servings of jelly. What day would you run out of both peanut butter and jelly

1 answer:

7 0

If Don eats one serving a day of both he will run out of jelly on day 40
of peanut butter on day 72
if he makes a peanut butter and jelly every day he will run out on day 40

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8× what =2

sergejj [24]

Answer:

8*1/4= 2

A) 0.071

B) 0.48

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3 years ago

Please help me find the slopes and explain rise and run.Its confusing for me im in algebra 1 by the way and the rise and run con

Tju [1.3M]

Graph 1: -3 is the slope
Graph 2: 4/5 is the slope

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3 years ago

A 6-pound bag of chocolate candies costs $14.04. What is the unit price?

Ber [7]

Answer:

2.34 per pound is unit price

Step-by-step explanation:

14.04 divided by 6 is 2.34

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4 years ago

Find derivative problem<br> Find B’(6)

dalvyx [7]

Answer:

$B^\prime(6) \approx -28.17$

Step-by-step explanation:

We have:

$\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)$

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

$\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]$

We can move the constant outside:

$\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]$

Now, we will utilize the product rule. The product rule is:

$(uv)^\prime=u^\prime v+u v^\prime$

We will let:

$\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t$

Then:

$\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1$

(The derivative of u was determined using the chain rule.)

Then it follows that:

$\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}$

Therefore:

$\displaystyle B^\prime(6) =24.6[(\frac{\pi}{10}\cos(\frac{\pi (6)}{10}))(8-(6))- \sin(\frac{\pi (6)}{10})]$

By simplification:

$\displaystyle B^\prime(6)=24.6 [\frac{\pi}{10}\cos(\frac{3\pi}{5})(2)-\sin(\frac{3\pi}{5})] \approx -28.17$

So, the slope of the tangent line to the point (6, B(6)) is -28.17.

5 0

3 years ago

Sara hina and Arslan have a total of RS 390in their wallet . Sara has Rs. 7more than Hina .Arslan has 3 times what sara has . Ho

Brums [2.3K]

Answer:Sara hina and Arslan Have RS79.4,RS 72.4 and RS238.2 respectively.

Step-by-step explanation:

Step 1

Let the amount that hina has be x

the amount that sara has be represented as 7+x

and the amount that Arslan have be represented as 3(7+x)

such that the total amount in their wallet which is 390 can be expressed as

x+7+x + 3(7+x)=390

Step 2

Solving

x+7+x +21+3x=390

5x+28=390

5x==390-28

x=362/5=72.4

Hina has RS 72.4

Sara =7+x==72.4+77= RS 79.4

Arslan =3(7+x)=3 x 79.4=RS 238.2

5 0

3 years ago