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Step2247 [10]
3 years ago
6

Don has 72 servings of peanut butter and 40 servings of jelly. What day would you run out of both peanut butter and jelly

Mathematics
1 answer:
algol [13]3 years ago
7 0
If Don eats one serving a day of both he will run out of jelly on day 40
of peanut butter on day 72
if he makes a peanut butter and jelly every day he will run out on day 40
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Katie is reading a 200-page book that is divided into 5 chapters. The bar graph shows the number of pages in each
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Answer:

I don't see any bar graph, can you add it please?

Step-by-step explanation:

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3 years ago
What is the mean of the values in the dot plot?<br><br> Enter your answer in the box.
Alona [7]

Answer:45.3333333333333333333333333333333333333333333...

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3 years ago
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On the first day of a trip, the Brenner family hikes 2.8 miles. On the second day, they hike 1.25 along a trail. They take a bre
Vadim26 [7]
They hiked more on the 2nd day because they are retracing their steps.
8 0
3 years ago
Write an equation.
schepotkina [342]

Given:

y is proportional to x.

y=10 and x=8.

To find:

The constant of proportionality and the equation for the proportional relationship.

Solution:

y is proportional to x.

y\propto x

y=kx               ...(i)

Where, k is the constant of proportionality.

Putting y=10 and x=8, we get

10=k(8)

\dfrac{10}{8}=k

\dfrac{5}{4}=k

Putting k=\dfrac{5}{4} in (i), we get

y=\dfrac{5}{4}x

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5 0
3 years ago
You measure the lifetime of a random sample of 25 rats that are exposed to 10 Sv of radiation (the equivalent of 1000 REM), for
Slav-nsk [51]

Answer:

CI 95%(μ)= [13.506 ; 14.094]

Step-by-step explanation:

The confidence interval (CI) formula is:

CI (1-alpha) (μ)= mean+- [(Z(alpha/2))* σ/sqrt(n)]

alpha= is the proportion of the distribution tails that are outside the confidence interval. In this case, 5% because 100-90%

Z(5%/2)= is the critical value of the standardized normal distribution. In this case is 1.96

σ= standard deviation. In this case 0.75 day

mean= 13.8 days

n= number of observations . In this case 25

Then, the confidence interval (90%) is:

CI 95%(μ)= 13.8+- [1.96*(0.75/sqrt(25)]

CI 95%(μ)= 13.8+- [1.96*(0.75/5) ]

CI 95%(μ)= 13.8+- (0.294)

CI 95%(μ)= [13.8-0.294 ; 13.8+0.294]

CI 95%(μ)= [13.506 ; 14.094]

4 0
3 years ago
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