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lesantik [10]
3 years ago
5

The water level in a plastic pool changed by -8 gallons each hour due to small hole in the bottom after 6 hours the pool contain

ed 132 gallons how much water was in the pool originally
Mathematics
1 answer:
oee [108]3 years ago
7 0

Answer:

180

Step-by-step explanation:

When you multiply the about lost per hour by the amount of time, you get the amount lost total.

6*8=48

then you add that to the amount in the pool now, and you have the original amount.

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For which pair of functions is (g circle f) (a) = StartAbsoluteValue a EndAbsoluteValue minus 2?
Setler79 [48]

Answer:

Option C is the answer.

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3 0
3 years ago
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Karen surveyed students in one middle school about their favorite band. Of the 1,156 students in the middle school, 65 sixth-gra
ValentinkaMS [17]
I believe the answer is B.



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3 0
3 years ago
find an equation of the tangent plane to the given parametric surface at the specified point. x = u v, y = 2u2, z = u − v; (2, 2
Alexxandr [17]

The surface is parameterized by

\vec s(u,v) = x(u, v) \, \vec\imath + y(u, v) \, \vec\jmath + z(u, v)) \, \vec k

and the normal to the surface is given by the cross product of the partial derivatives of \vec s :

\vec n = \dfrac{\partial \vec s}{\partial u} \times \dfrac{\partial \vec s}{\partial v}

It looks like you're given

\begin{cases}x(u, v) = u + v\\y(u, v) = 2u^2\\z(u, v) = u - v\end{cases}

Then the normal vector is

\vec n = \left(\vec\imath + 4u \, \vec\jmath + \vec k\right) \times \left(\vec \imath - \vec k\right) = -4u\,\vec\imath + 2 \,\vec\jmath - 4u\,\vec k

Now, the point (2, 2, 0) corresponds to u and v such that

\begin{cases}u + v = 2\\2u^2 = 2\\u - v = 0\end{cases}

and solving gives u = v = 1, so the normal vector at the point we care about is

\vec n = -4\,\vec\imath+2\,\vec\jmath-4\,\vec k

Then the equation of the tangent plane is

\left(-4\,\vec\imath + 2\,\vec\jmath - 4\,\vec k\right) \cdot \left((x-2)\,\vec\imath + (y-2)\,\vec\jmath +  (z-0)\,\vec k\right) = 0

-4(x-2) + 2(y-2) - 4z = 0

\boxed{2x - y + 2z = 2}

6 0
2 years ago
Only one function exists that is both an even function and an
Ghella [55]

9514 1404 393

Answer:

  f(x)=0

Step-by-step explanation:

For the function to be both even and odd, you must have ...

  f(-x) = f(x) = -f(-x)

Adding f(-x) we have ...

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Then dividing by 2 and recognizing f(-x) = f(x), we have ...

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8 0
3 years ago
Express 900 as a product of its prime factors in index form. Write the prime factors in ascending factors.
Lina20 [59]

Answer:

900 = 2 * 2 * 3 * 3 * 5 * 5 = 2^2 * 3^2 * 5^2

Step-by-step explanation:

900/2 = 450

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25/5 = 5

5/5 = 1

900 = 2 * 2 * 3 * 3 * 5 * 5 = 2^2 * 3^2 * 5^2

7 0
3 years ago
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