Answer:
The tank is a cone, so the radius of the cross section increases linearly with h
At y=0, r=4 and at y=11, r=0
So
r(y)=4/11 (11−y)
A(y)=π[4(11−y)11]^2
Integral will be:
11∫0 (1000)(9.8)(4πy^2)(25)(11−y)dy
Step-by-step explanation:
7.85+q≤ -18.15
Simplify both sides of the inequality
q+7.85 ≤ -18.15
Subtract 7.85 from both sides
q+7.85-7.85 ≤ -18.15-7.85
Q ≤ -26
I hope that's help !
When you plot the points and use the vertical line test, you'll see that none of the vertical lines go through two points. Therefore verifying that this set of points represents a function.
Answer:
I came to the answer of 6.
