All categories

2 years ago

Gordo ate 3 twinkles and 1 cupcake,

2 answers:

5 0

To answer this, we can use as 1 Twinkie as x, and a cupcake as y. First, we can make an equation. Since 3 Twinkie’s and 1 cupcake add up to 750 calories, we have: 3x+y=750. Since a cupcake has twice the amount of calories, then 2x=y. Next, we can substitute the y, and we get:
3x+2x=750
Combining like terms
5x=750
Divide by 5 on both sides
x = 150
Since a cupcake has twice the amount of calories than a Twinkie, then one Twinkie is 150*2=300.

marin [14]2 years ago

4 0

Answer:

there are 150 in a twinkie and 300 in a cupcake

Step-by-step explanation:

3 x 150 = 450 then 150 x 2 = 300

You might be interested in

Please help with these quick

drek231 [11]

To determine whether 10a-10c are true or false, you first need to know how to find the volume of the shoebox and the volume of the crate.

The equation for volume is l × w × h where l is the length, w is the width, and h is the height.

So, the volume of the shoebox is

V = l × w × h
V = 12 × 6 × 4
V = 288 cubic inches.

To find the volume of the crate, we simply multiply the volume of one shoebox by 20, as the crate holds 20 shoeboxes.

228 × 20 = 4560 cubic inches.

10a. Each shoebox has a volume of 22 cubic inches. False. The volume is 228 cubic inches.

10b. Each crate has a volume of about 440 cubic inches. False. The volume of each crate is 4560 cubic inches.

10c. If the crate could hold 27 shoeboxes, the volume of the crate would be about 7,776 cubic inches.

For this one, let's do some more math. Since we figured out the volume of a crate holding 20 shoeboxes is 4560 cubic inches, let's do the same thing to find the volume of a crate holding 27 shoeboxes.

228 × 27 = 6156 cubic inches.

False. The volume of a crate holding 27 shoeboxes would be 6156 cubic inches.

11 part A:

Each term above describes the term below, but the term below doesn't necessarily describe the term above.

The choice of terms is : trapezoid, triangle, rhombus, parallelogram

Before we do anything else, let's define our terms, as well as the ones used in the diagram.

Trapezoid - A four sided shape with a pair opposite parallel sides.
Triangle - A shape with three sides.
Rhombus - A shape with four equal straight sides.
Parallelogram - A quadrilateral with two sets of parallel sides.
Quadrilateral - A four-sided shape with four angles.
Square - A four-sided shape with all four sides the same length, and all four angles are the same size.

The first term is quadrilateral. From this, we can determine that the term triangle won't be used at all, as it's a three-sided figure, whereas a quadrilateral is a four-sided figure. This leaves trapezoid, rhombus, and parallelogram as our terms.

A trapezoid is a quadrilateral, because it has four sides, but it can't be a rhombus or parallelogram, so it goes in the first open box.

A parallelogram is a trapezoid, because it has a pair of opposite parallel sides, but it can't be a rhombus, because it doesn't necessarily have all equal sides, so it goes in the second open box.

A rhombus is a parallelogram, because it has two sets of parallel sides, and goes in the third open box.

So, from top box to bottom box, the order the term go is
Quadrilateral
Trapezoid
Parallelogram
Rhombus
Square

3 0

3 years ago

ABCD is a parallelogram. E is the point where the diagonals AC and BD meet. Prove that triangle ABE is congruent to triangle CDE

Darina [25.2K]

ABCD is a parallelogram Given
AE=CE, BE=DE The diagonals of a parallelogram are bisect each other
∠AEB=∠CED Vertical angles are congruent
ΔABE is congruent to ΔCDE SAS theorem

5 0

3 years ago

Read 2 more answers

I WILL GIVE A BRANLIEST! What is the graph of the functions? y=2*2^x y=-2*5^x

tekilochka [14]

For this case what you should know is that both functions are of the potential type.
We have then that
y = 2 * 2 ^ x
This function grows exponentially upwards.
y = -2 * 5 ^ x
This function grows exponentially downwards.
Answer
See attached graphics.

4 0

3 years ago

I need help with #61 to #64 ASAP please and thank you …. Could someone please help me with it… I need to get it done ASAP

aivan3 [116]

Problem 61

The nth triangular number is

T(n) = n(n+1)/2

I'll rewrite this into

T(n) = 0.5n(n+1)

The triangular number right after this is

T(n+1) = 0.5(n+1)(n+2)

I replaced every n with n+1 and simplified

Let's see what we get when we add up the two expressions

T(n) + T(n+1)

0.5n(n+1) + 0.5(n+1)(n+2)

0.5n^2+0.5n + 0.5(n^2+3n+2)

0.5n^2 + 0.5n + 0.5n^2 + 1.5n + 1

n^2+2n+1

(n+1)^2

This shows that the sum of any two consecutive triangular numbers results in a square number

Here's a few examples

0+1 = 1
1+3 = 4
3+6 = 9
6+10 = 16
10+15 = 25

Note each sum is a perfect square, which visually would plot out a square figure.

For quick reference, the set of the first few triangular numbers is {0, 1, 3, 6, 10, 15, 21, 28, 36, 45, 55,...}

<h3>Answer: Square number</h3>

==========================================================

Problem 64

Let's say we go with n = 5.

This means,

T(n) = 0.5n(n+1)

T(n-1) = 0.5(n-1)(n-1+1)

T(n-1) = 0.5n(n-1)

T(5-1) = 0.5*5(5-1)

T(4) = 10

This says that when n = 5, the 4th triangular number is 10

Triple that result and add on n = 5

3*T(4) + n = 3*10+5 = 35

This result is beyond obvious which category of figurate number it belongs to. It's not a triangular number since it's not in the form n(n+1)/2. It's not a square number either.

Through a bit of trial and error, you should find it's a pentagonal number

Pentagonal numbers are of the form n(3n-1)/2

If you plugged n = 5 into that, it leads to 35

n(3n-1)/2 = 5*(3*5-1)/2 = 5*14/2 = 70/2 = 35

The diagram shown below represents the first few pentagonal numbers. The number of blue dots corresponds to the pentagonal number itself. Note the equal spacing when dealing with dots on each segment (eg: some interior blue dots are midpoints, others are quarter points, etc.)

<h3>Answer: Pentagonal number</h3>

8 0

2 years ago

Pls help me I rlly don’t get it :(

zhenek [66]

Step-by-step explanation:

Use SOH-CAH-TOA.

Sine = Opposite / Hypotenuse

Cosine = Adjacent / Hypotenuse

Tangent = Opposite / Adjacent

Let's start with #12. The hypotenuse is 18. The side adjacent to ∠B is 6. Since we have the adjacent side and hypotenuse, we should use cosine.

cos B = 6/18

Solving for B:

B = cos⁻¹(6/18)

Using a calculator:

B ≈ 70.5°

Now let's do #14. The side adjacent to ∠B is 19, and the side opposite of ∠B is 22. Since we have the adjacent side and opposite side, we should use tangent.

tan B = 22/19

Solving for B:

B = tan⁻¹(22/19)

Using a calculator:

B ≈ 49.2°

8 0

3 years ago