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2 years ago

I need help on this asap pls help??

Mathematics

1 answer:

Sedaia [141]2 years ago

3 0

Answer:

Step-by-step explanation:

Your answer is correct, but you need both the positive and the negative of the square root of 3. You only listed the positive one.

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Please someone help ASAP what is the correct answer ?

kramer

Answer:

It is x2 -4 because it correct

6 0

3 years ago

Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find

Papessa [141]

Answer:

1) $\text{P(at least one boy and one girl)}=\frac{3}{4}$

2) $\text{P(at least one boy and one girl)}=\frac{3}{8}$

3) $\text{P(at least two girls)}=\frac{1}{2}$

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To Find : The probability of each event.

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

1) P(at least one boy and one girl)

Favorable outcome = BBG, BGB, BGG, GBB, GBG, GGB=6

$\text{P(at least one boy and one girl)}=\frac{6}{8}$

$\text{P(at least one boy and one girl)}=\frac{3}{4}$

2) P(at least one boy and one girl)

Favorable outcome = BBG, BGB, GBB=3

$\text{P(at least one boy and one girl)}=\frac{3}{8}$

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

$\text{P(at least two girls)}=\frac{4}{8}$

$\text{P(at least two girls)}=\frac{1}{2}$

4 0

4 years ago

Read 2 more answers

In ALMN, the measure of ZN=90°, MN = 5 feet, and LM = 7-3 feet. Find the measure

Mazyrski [523]

Answer:43.2

Step-by-step explanation:

6 0

3 years ago

Solve by substitution x-y=-11 y+7=-2x

Bess [88]

x - y = - 11 .............( 1 )

y + 7 = - 2x ...............( 2 )

from equation ( 1 )

x - y = - 11

x = -11 + y ...........( 3)

putting x in equation ( 2 )

y + 7 = - 2 x

y + 7 = -2 ( -11 + y ) y + 7 = 22 - 2 y y + 2 y =22 - 7

3 y = 15 y = 15 / 3

putting value of y in equation 3

x = -11+ ( 13 /5 ) x = -33 /3 + 15 / 3 ( l.c.m)

x = -17 / 5

check

x = -11 + y

- 17 / 5 = -11 + 13 / 5

-17 /5 = -17 / 5

4 0

3 years ago

EFGH is a rhombus. Given EG = 16 and FH = 12, what is the length of one side of the rhombus?

Black_prince [1.1K]

Answer:

Step-by-step explanation:

It is given that EFGH is a rhombus and EG = 16 and FH = 12.

We know that the diagonals of the rhombus are the perpendicular bisectors, therefore OF=6, OH=6, OE=8 and OG=8.

Now, using the Pythagoras theorem in ΔOFG, we have

$(FG)^{2}=(OG)^{2}+(OF)^{2}$

$(FG)^{2}=(8)^{2}+(6)^{2}$

$(FG)^2=64+36$

$FG=\sqrt{100}$

$FG=10$

Thus, the value of the side of the rhombus will be 10 units.

Hence, option C is correct.

3 0

3 years ago

Read 2 more answers