All categories

2 years ago

Solve the inequality for x. 5 is greater than or equal to 4x+9 . simplify as much as possible

Mathematics

2 answers:

gayaneshka [121]2 years ago

7 0

Answer:

For this we need to solve using the transposition method

Step-by-step explanation:

We need to shift variables and constants from the RHS to LHS sgregating the x. + becomes - and x becomes /

natima [27]2 years ago

5 0

Answer:

X ≤ - 1

Step-by-step explanation:

5 ≥ 4x + 9 ( subtract 9 from both sides )

- 4 ≥ 4x ( divide both sides by 4 )

- 1 ≥ x , then

x ≤ - 1

You might be interested in

Which of the following is in order from smallest to largest?

kirill115 [55]

Answer:

-5,-8,-10,1,7

Step-by-step explanation:

6 0

3 years ago

Bobcat park is a rectangular park with an area of 5 1/5 square miles.Its width is 1 19/20 miles. How long is the park

mel-nik [20]

area = length times width, so length = area / width

5 1/5 mi^2 5.2 mi^2

Here, length = ------------------- = --------------- = 2.66666... mi = 2 2/3 mi (answer)

1 19/20 mi 1.95 mi

4 0

3 years ago

Please help me on this !!!! tysm

ss7ja [257]

Answer:

21.5?

the more i think the more i believe it

5 0

2 years ago

Which one is it? I’m taking a Quiz and I’m not prepared :(

Tom [10]

Answer:

Pretty sure it's the second one. Hope this helps!

Step-by-step explanation:

5 0

2 years ago

R= m/2 (c + K) for k

Wewaii [24]

Answer:

$\bold{K=\frac{2r}m-c=\frac{2r-cm}m}$

Step-by-step explanation:

$\bold{r= \frac m2 (c + K)}\\^{\div\frac m2}\qquad^{\div\frac m2}\\ \bold{r\cdot\frac2m=c+K}\\{}\ ^{-c}\qquad^{-c}\\\bold{\frac{2r}m-c=K}$

Or if you mean r= m/[2(c + K)]

$\bold{\quad r\ =\ \frac m{ 2(c + K)}}\\^{\cdot(c+K)}\quad^{\cdot(c+K)}\\ \bold{r(c+K)=\frac m2}\\{}\qquad ^{\div r}\qquad^{\div r}\\\bold{c+K=\frac m2\cdot\frac1r}\\{}\quad^{-c}\qquad^{-c}\\\bold{K=\frac m{2r}-c}$

5 0

2 years ago