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andrey2020 [161]
2 years ago
12

How does Earth’s orbit affect the weather and climate?(1 point)

Biology
2 answers:
Brums [2.3K]2 years ago
8 0

Earth's orbit affects weather and climate why summers are hottest in the Southern Hemisphere when Earth is closer to the Sun. We need to know that .......

<h3>Weather and climate</h3>

When in the Northern Hemisphere it is winter, in the Southern Hemisphere it is summer. Likewise, when it is spring in one hemisphere, it will be autumn in the other. This is precisely because of the position that each hemisphere occupies in relation to the Sun in that period, which determines the amount of solar irradiation it is receiving.

With this information, we can say that the tilt of the earth is very important for the climate and weather of the planet, because when the Northern Hemisphere is closer to the sun, the summer will be hotter, and consequently in the Southern Hemisphere, it will be winter.

Learn more about Earth's orbit in brainly.com/question/15022652

frez [133]2 years ago
5 0

Answer: summers are hotter in the Southern Hemisphere when earth is closer to the sun

Explanation:

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You are a botanist looking at the plant color in a new breed of Snapdragon. The two parent plants are Blue and Green and when yo
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Answer:

Incomplete dominance is the inheritance pattern where the dominant allele did not mask the recessive allele completely and form a mix of both alleles. Here the inheritance is the incomplete inheritance. The ratio of F2 generation is 1:2:1.

Given:

R1R1 = 42

R2R2 = 39

R1R2 = 86

Total R1 alleles = 2*42+86 = 170

Total R2 alleles = 2*39+86 = 164

Total alleles = 334

Frequency of allele R1 = 170/334 = 0.51

Frequency of allele R2 = 164 / 334 = 0.49

Expected number of each phenotype:

Total population = 167

Blue = R1R1 = 0.51 * 0.51 * 167 = 43.44

Green = R2R2 = 0.49 * 0.49 * 167 = 40.10

Cyan = 2*R1*R2 = 2*0.51*0.49*167 = 83.46

Phenotype     Observed(O)    Expected (E)    O-E      (O-E)2     (O-E)2/E

Blue                 42                   43.44               -1.44       2.0736     0.0477

cyan                86                   83.46                 2.54     6.4516     0.0773

green              39                    40.1                    -1.1       1.2100      0.0302

Total              167                     167                                               0.1552

Chi-square value = 0.155

Degrees of freedom = no. of phenotypes – 1

Df = 3-1 = 2

Critical value = 5.99

Chi-square value of 0.155 is less than the critical value of 5.99. So we accept the null hypothesis.

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