“Stephen attempted to use the elimination method to solve the system of equations below but he made a mistake. What is it?
1 answer:
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Answer <u>(assuming it can be in slope-intercept form)</u>:
Step-by-step explanation:
1) First, we need to find the slope of the given equation. To do that easily, convert it to slope-intercept form, represented by the formula . Isolate y:
The number in place of , or the coefficient of the x-term, represents the slope of the equation. So, the slope of the given equation is -2.
Lines that are parallel share the same slope. So, the slope of the new equation will be -2 as well.
2) Now, remember that the slope-intercept form is represented by the formula . In order to write an equation of a line using that formula, we need to substitute values for
and
. We know
is the slope, so we already know what that equals. Now, we just need to find
.
To do that, substitute -2 for in the slope-intercept formula. Additionally, substitute the x and y values of the point (2,6) for the x and y in the formula as well. This sets up the equation so that we can isolate
and find its values:
So, = 10.
3) Substitute values for and
into the slope-intercept formula to write the slope-intercept form of the line:
A function that depicts depreciation can be represented as equations, graphs and tables.
<h3>The yearly value of each car for the first five years</h3>The functions are given as:
Where:
C = 5895 --- the initial value of the car
r = 22% --- the rate of depreciation
For the first 5 years, the values of t = 1, 2, 3, 4 and 5
For the first function, we have:
For the second function, we have
So, the table of values is:
See attachment for the graphs of the two functions
<h3>Interpreting the graphs</h3>The graph of car 1 increases up to C(t) = 5895, and then remains constant as the value of t increases while the graph of car 2 follows an exponential pattern.
This means that, the graph 2 that follows an exponential pattern is more realistic
<h3>The worth of the cars after 5 years</h3>From the table, the worth of car 1 is $5892.0, while the worth of car 1 is $1702.0
Read more about graphs and functions at:
