Answer:
a. 4/21
b. 4/7
Step-by-step explanation:
Please kindly check the attached files for explanation.
Write a system of equations and solve.
x + y = 10
5x + 10y = 90
Multiply and combine equations
-5x - 5y = -50
5x + 10y = 90
------------------
5y = 40
y = 8
x = 2
There are 2 nickels and 8 dimes in the jar. Hope this helps! :)
I have attached screenshots for the complete question as well as the diagram associated with it.
Answer:point C
Explanation:A plane and a line can either:
1- have no intersection
2- intersect in a point
3- intersect in a line in case the whole line is found in this plane
For the given:
We can see that line CG does not belong to the plane ABCD, however, they both intersect.
This means that the intersection between them is a point.
We can note that the only point common between the line and the plane is point C.
Therefore, plane ABCD intersects line GC at point C
Hope this helps :)
The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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