Answer:
D) f(x) = 6x
Step-by-step explanation:
Just subisute values that will work
one easy way is to make one sides equal to only one of the placeholders, like y, and then lug in values in for x exg
x+2y=3
subtract x from both sides
2y=3-x
divideb bith sides by 2
y=-1/2x+3
subsitute valudes for x and get values for y
if x=2 then
y=-1/2(2)+3
y==-1+3
y=2
when x=2, y=2
when y=0 then y=3
Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
I THINK IM WRONG BUT
Step-by-step explanation:
X3 NUZZELS POINCES ON U
Answer:
I would assume you're referring to this test? if so the answer is
a, d and e
