Answer:
1) -15/4
2) -15/2
Step-by-step explanation:
1) Let u=4t. Then the limits become u=4(0)=0 and u=4(4)=16. Also du=4 dt upon differentiating the equation.
So the integral can be written as
Integral( 1/4 f(u) , u=0 to u=16)
We are given Integral( f(u) , u=0 to u=16) is -15. So a fourth of that is our answer for the first question.
2) Let u=t^2. Then the limits become u=(0)^2=0 and u=(4)^2=16. Also upon differentiating we obtain equation du =2 t dt.
So the integral becomes
Integral( 1/2 f(u) , u=0 to u=16).
We are given Integral( f(u) , u=0 to u=16) is -15. So a half of that is our answer for the second question.
