Answer:
Step-by-step explanation:
17) HI ≅ UH ; GH ≅ TU ; GI ≅ TH
ΔHGI ≅ ΔUTH by Side Side Side congruent
∠G ≅ ∠T ; GI ≅ TH ; ∠GIH ≅ ∠THU
ΔHGI ≅ ΔUTH by Angel Side Angle congruent
19) IJ ≅ KD ; IK ≅ KC ; KJ ≅ CD
ΔIJK ≅ ΔKDC by Side Side Side congruent
∠J ≅ ∠D ; IJ ≅ KD ; ∠I ≅ ∠DKC
ΔIJK ≅ ΔKDC by Angle Side Angle congruent
Answer:
the figure could be a rhombus because the 2 lines of symmetry bisect the angles
Step-by-step explanation:
Can someone please help me answer this problem
Answer:
We taking the same final exam
Step-by-step explanation:
I don’t know the answer that’s why I came here
Answer:
3x^2-x+5.2f\left(-3\right)-f\left(4\right) =
3x^2-x-19.6f
Step-by-step explanation:
3x^2-x+5.2f\left(-3\right)-f\left(4\right)
=3x^2-x-5.2f\cdot \:3-f\cdot \:4
=3x^2-x-15.6f-4f
=3x^2-x-19.6f
