Pls help ASAP!!!!!!!!!
2 answers:
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Answer:
see explanation
Step-by-step explanation:
Given
2x² + x - 1 = 2 ( subtract 2 from both sides )
2x² + x - 3 = 0
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 2 × - 3 = - 6 and sum = + 1
The factors are - 2 and + 3
Use these factors to split the x- term
2x² - 2x + 3x - 3 = 0 ( factor the first/second and third/fourth terms )
2x(x - 1) + 3(x - 1) = 0 ← factor out (x - 1) from each term
(x - 1)(2x + 3) = 0
Equate each factor to zero and solve for x
x - 1 = 0 ⇒ x = 1
2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = -
Answer:
This system has no solution:
y = x²
y = 0 · x - 1
Step-by-step explanation:
Hi there!
I propose these two equations:
y = x²
y = 0 · x - 1
This system has no solution because in the quadratic function "y" is always positive for every value of "x", while in the linear function "y" is always -1 for every value of "x". Then, there will not be a pair (x,y) shared by both functions.
In other words, there is no value of "x" that satisfies this expression:
x² = 0 · x - 1
In the attached graphic, you can see that both curves never touch (in red is the quadratic function and in blue is the linear function), hence, the system has no solution.
Have a nice day!
