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vfiekz [6]
3 years ago
10

Pls help ASAP!!!!!!!!!

Mathematics
2 answers:
lara31 [8.8K]3 years ago
6 0
67-52= 15
82-67= 15
97-82= 15
52-15=37
(1,37) I think it’s 37 per hour but if it’s not I’m sorry!
vovangra [49]3 years ago
4 0

Answer:

do you still need help ??

Step-by-step explanation:

You might be interested in
Please help idk nothing
Rainbow [258]
Convert 9 1/2 into a mixed fraction: 19/2.
Now, multiply with 6 which in fraction form is 6/1
19/2 times 6/1 equals 114/2

Now you can divide 114/2 which is 57 inches squared.

Have a good day ! :)
7 0
3 years ago
Look at the image. ( Ill give brainliest to best answer.)
nalin [4]
C. 1 solution hope it helps
3 0
3 years ago
For each pair figures, find the ratio of the area of the first figure to the area of the second. 14mm 7mm
Paraphin [41]

The ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

<h3>Ratio of the areas of similar figures </h3>

From the question, we are to determine the ratio of the area of the<u> first figure</u> to the area of the <u>second figure</u>

<u />

The two figures are similar

From one of the theorems for similar polygons, we have that

If the scale factor of the sides of <u>two similar polygons</u> is m/n then the ratio of the areas is (m/n)²

Let the base length of the first figure be ,m = 14 mm

and the base length of the second figure be, n = 7 mm

∴ The ratio of their areas will be

(\frac{14 \ mm}{7 \ mm})^{2}

= \frac{196 \ mm^{2} }{49\ mm^{2} }

=\frac{4}{1}

= 4:1

Hence, the ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446

8 0
2 years ago
What equal 27 on gif
natali 33 [55]
Then that would be 3 and 9.
8 0
3 years ago
Given: Triangles ABC and DBC are isosceles, m∠BDC = 30°, and m∠ABD = 155°. Find m∠ABC, m∠BAC, and m∠DBC.
just olya [345]
∠BDC=30, so ∠CBD + ∠BCD=180-30=150
ΔDBC is isosceles, so ∠CBD=∠BCD=half of 150=75
∠ABC=∠ABD-∠CBD=155-75=80
ΔABC is isosceles, so ∠ABC=∠ACB=80
∠BAC=180-80-80=20
7 0
3 years ago
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