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3 years ago

What is x? 3x-5=10 please help and thank you

Mathematics

2 answers:

nika2105 [10]3 years ago

8 0

Answer:

x=5

Step-by-step explanation:

Move all terms not containing x to the right side of the equation.

Add 5 to both sides of the equation.

3x = 10 + 5

Add 10 and 5

3x = 15

Divide each term in 3x = 15 by 3 and simplify.

3x/3 = 15/3

Simplify the left side

Cancel the common factor of 3

x = 15/3

Divide 15 by 3

x = 5

Maru [420]3 years ago

3 0

Answer:

Step-by-step explanation:

3x - 5 = 10

3x = 15

x = 5

I hope it helps bye, good luck

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Solving Square Root Worksheet (x - k)^2 Part 3

erastova [34]

Answer:

7. x = -2 +/- $4i\sqrt{5}$

8. x = 2 or x = 6

9. x = -2 +/- $\frac{\sqrt{26} }{2} i$

10. t = -3 +/- $\sqrt{35}$

Step-by-step explanation:

7. Subtract 320 from both sides: 4(x + 2)^2 = -320

Divide by 4: (x + 2)^2 = -80

Square root both sides: x + 2 = +/- $\sqrt{-80}$ . We need to add the imaginary i to this: +/- $\sqrt{-80}$ = +/- $i\sqrt{80}$ = +/- $4i\sqrt{5}$

Subtract 2 from both sides: x = -2 +/- $4i\sqrt{5}$

8. Add 18 to both sides: 7(x - 4)^2 = 28

Divide by 7: (x - 4)^2 = 4

Square root both sides: x - 4 = +/- 2

Add 4 to both sides: x = 4 +/- 2 ⇒ x = 2 or x = 6

9. Add 5 to both sides: -2(x + 2)^2 = 13

Divide by -2: (x + 2)^2 = -13/2

Square root both sides: x + 2 = +/- $\sqrt{-13/2}$ . We again need i: +/- $\sqrt{-13/2}$ = +/- $i\sqrt{13/2} =$ +/- $\frac{\sqrt{26} }{2} i$

Subtract 2 from both sides: x = -2 +/- $\frac{\sqrt{26} }{2} i$

10. Multiply by 5 on both sides: (t + 3)^2 = 35

Square root both sides: t + 3 = +/- $\sqrt{35}$

Subtract 3: t = -3 +/- $\sqrt{35}$

Hope this helps!

3 0

4 years ago

Read 2 more answers

A small radio transmitter broadcasts in a 31 mile radius. If you drive along a straight line from a city 38 miles north of the t

andreyandreev [35.5K]

9514 1404 393

Answer:

63.7% or 33.35 miles

Step-by-step explanation:

The hint suggests that we find the points where the drive begins and ends picking up the transmitter. We suspect both of those points will have irrational coordinates, so finding the distance between them will involve dealing with squares and roots of irrational numbers. We want to see if there's an easier way.

The distance from the transmitter to the path being driven can be found using the "distance to a line" formula. First, we need the equation of the line in general form. In intercept form, it is ...

y/38 +x/36 = 1

19x +18y -684 = 0 . . . . . . multiply by LCM(36, 38) and subtract that amount

Then the distance from the origin to the line is ...

d = |19·0 +18·0 -684|/√(19² +18²) = 685/√685 ≈ 26.1243

The distance (x) along the line from the point where the transmitter is first picked up until the point of closest approach can be found from the Pythagorean theorem:

x² + (26.1243)² = 31²

x² = 31² -(684/√685)² = 190429/685

x ≈ 16.6733

The driving distance for which the transmitter is picked up is twice this, so is ...

2x = 2(16.6733) ≈ 33.3466 . . . miles

The total drive length is also given by the Pythagorean theorem:

drive length = √(36² +38²) = √2740 ≈ 52.3450 . . . miles

Then the fraction of the drive during which the signal is picked up is ...

fraction = (33.3466 mi)/(52.3450 mi) ≈ 0.6371 ≈ 63.7%

The signal is picked up for 33.35 miles, about 63.7% of the drive.

______

The intercept-form equation for a line is ...