How do I solve this question?

Please help me solve problem 8

mixas84 [53]

The answer is A because when a question asks how much is left it typically means that you will need to subtract.

5 0

3 years ago

Read 2 more answers

I need help on this aswell

Katena32 [7]

Answer:

Graph C

Step-by-step explanation:

Hi there!

The given linear equations are organized in slope-intercept form: $y=mx+b$ where m is the slope of the line and b is the y-intercept, or the value of y when the line crosses the y-axis.

y = 2x + 4

Here, the b value is 4. Therefore, the y-intercept of this line is 4.

y = -3x - 2

Here, the b value is -2. Therefore, the y-intercept of this line is -2.

To identify the graph that models these equations, we just have to look for the graph where the lines cross the y-axis at 4 and -2.

The only graph that does this is graph C.

I hope this helps!

8 0

2 years ago

A bird is flying 10 feet above sea level, while a shark swims 15ft below sea level. How far is the bird from the shark?

kondaur [170]

Answer:

25 ft

Step-by-step explanation:

5 0

2 years ago

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Patrick has just finished building a pen for his new dog. The pen is 3 feet wider than it is long. He also built a doghouse to p

zalisa [80]

General Idea:

(i) Assign variable for the unknown that we need to find

(ii) Sketch a diagram to help us visualize the problem

(iii) Write the mathematical equation representing the description given.

(iv) Solve the equation by substitution method. Solving means finding the values of the variables which will make both the equation TRUE

Applying the concept:

Given: x represents the length of the pen and y represents the area of the doghouse

Statement 1: "The pen is 3 feet wider than it is long"

$Length \; of\; the \; pen = x\\ Width \; of\; the\; pen=x+3$

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Statement 2: "He also built a doghouse to put in the pen which has a perimeter that is equal to the area of its base"

$Area \; of\; the\; Dog \; house=y\\ Perimeter \; of\; Dog\; house=y$

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Statement 3: "After putting the doghouse in the pen, he calculates that the dog will have 178 square feet of space to run around inside the pen."

$Area \; of \; the\; Pen - Area \;of \;the\;Dog \;House=\;Space\;inside\;Pen\\ \\ x \cdot (x+3)-y=178\\ Distributing \;x\;in\;the\;left\;side\;of\;the\;equation\\ \\ x^2+3x-y=178\Rightarrow\; 1^{st}\; Equation\\$

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Statement 4: "The perimeter of the pen is 3 times greater than the perimeter of the doghouse."

$Perimeter\; of\; the\; Pen=3\; \cdot \; Perimeter\; of\; the\; Dog\; House\\ \\ 2(x \; + \; x+3)=3 \cdot y\\ Combine\; like\; terms\; inside\; the\; parenthesis\\ \\ 2(2x+3)=3y\\ Distribute\; 2\; in\; the\; left\; side\; of\; the\; equation\\ \\ 4x+6=3y\\ Subtract \; 6\; and \; 3y\; on\; both\; sides\; of\; the\; equation\\ \\ 4x+6-3y-6=3y-3y-6\\ Combine\; like\; terms\\ \\ 4x-3y=-6 \Rightarrow \; \; 2^{nd}\; Equation\\$