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Romashka-Z-Leto [24]
2 years ago
6

How do I solve this question?

Mathematics
1 answer:
EastWind [94]2 years ago
5 0

Answer:

A

Step-by-step explanation:

throat bababy

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Answer:

I am still trying to pick between third-person limited and third-person omniscient...Let me know which one is right :)

Step-by-step explanation:

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A grocery store will only accept yellow onions that are at least 3 inches in diameter. A grower has a crop of onions with diamet
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<span>For the answer to the question above,this is a simple question.

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3 years ago
Find the exact value of cos theta​, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.
vova2212 [387]

Answer:

cos \theta = -\frac{8}{17}

Step-by-step explanation:

For this case we know that:

sin \theta = \frac{15}{17}

And we want to find the value for cos \theta, so then we can use the following basic identity:

cos^2 \theta + sin^2 \theta =1

And if we solve for cos \theta we got:

cos^2 \theta = 1- sin^2 \theta

cos \theta =\pm \sqrt{1-sin^2 \theta}

And if we replace the value given we got:

cos \theta =\pm \sqrt{1- (\frac{15}{17})^2}=\sqrt{\frac{64}{289}}=\frac{\sqrt{64}}{\sqrt{289}}=\frac{8}{17}

For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

cos \theta = -\frac{8}{17}

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3 years ago
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