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Crank
3 years ago
9

Write the equation of the line passing through the points (-3,7) and (-6,9)

Mathematics
1 answer:
algol [13]3 years ago
6 0

Answer:

y = -2/3x + 5

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The verticles of a triangle are the points R(3,c),Q(9,2) and R(3c,11) where c is constant. Given that angle PQR is 90​
IceJOKER [234]

Answer:

Step-by-step explanation:

Find c if ∠PQR = 90°?

I will ASSUME you mean point P is at (3. c)

slope of PQ is (2 - c) / (9 - 3) = (2 - c) / 6

slope of QR is (11 - 2) / (3c - 9) = 9 / (3c - 9)

perpendicular lines have negative reciprocal slopes.

(2 - c) / 6 = -1(3c - 9)/9

9(2 - c) = -6(3c - 9)

18 - 9c = -18c + 54

       9c = 36

         c = 4

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3 years ago
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ruslelena [56]
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3 years ago
Y varies directly as x. Y=42 when x=6. Find the value of y when x =15.
pentagon [3]

Answer:

y=120

Step-by-step explanation:

Y varies directly as x is written as

y \alpha x

introducing a constant

y=kx

<em>from</em><em> </em><em>the</em><em> </em><em>ques</em><em>tion</em><em>,</em><em> </em><em>whe</em><em>n</em><em> </em><em>y</em><em>=</em><em>4</em><em>8</em><em>,</em><em> </em><em> </em><em>x</em><em>=</em><em>6</em>

<em>sub</em><em>stitute</em><em> </em><em>it</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>form</em><em>ula</em>

<em>4</em><em>8</em><em>=</em><em>6</em><em>k</em>

<em>making</em><em> </em><em>k</em><em> </em><em>the</em><em> subject</em><em> </em><em>by </em><em>divi</em><em>ding</em><em> </em><em>thr</em><em>ough</em><em> </em><em>by</em><em> </em><em>6</em>

<em>\frac{48}{6}  =  \frac{6k}{6}</em>

k=48/6

k=8

<em>put</em><em> </em><em>the</em><em> </em><em>va</em><em>lue</em><em> </em><em>of</em><em> </em><em>k</em><em> </em><em>in</em><em> </em><em>the </em><em>expression</em><em> </em><em>y</em><em>=</em><em>kx</em>

<em>y</em><em>=</em><em>8</em><em>x</em>

from the question,the value of y when x=15 is given by

y=8×15

y=120.

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3 years ago
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