Large sphere's radius = R,
small sphere's radius = r, R = 8r
surface area of a sphere (SA) = 4×pi×radius^2
So what we need is the SA of the larger in terms of the smaller sphere, so if:
SA (of R) = 4×pi×R^2, then plug in "8r" for "R"...
SA = 4×pi×(8r)^2 = 4×3.14×64r^2
SA = 12.57×64r^2 = 804 r^2
Therefore the SA of the larger sphere is 804 times the SA of the smaller sphere.
I hope that makes sense!
Answer:
x = 13
Step-by-step explanation:
BH / YL = HN / LR
28 / 21 = 3x-7 / x+11
cross-multiply:
4x + 44 = 9x - 21
-5x = -65
x = 13
Answer:
87.28 cubic inches
Step-by-step explanation:
Leigh wants to fill the conical candle wax mold completely with candle wax.
We have to calculate the volume of the cone by the formula :

Here, V = volume
r = radius = 2.1 inches
h = height = 18.9 inches
By substituting these values given, into the formula

= (27.783)π
= 87.28 inch³
Conical mold can hold 87.28 inch³ candle wax.
Answer: B. 11/13
Step-by-step explanation:
So he starts out with 16, and picks out 3 of those 13. This means that he now has 13 socks in total in the drawer, so therefore, the answer could only be A or B. However, what makes it B, is that if he doesn't put them back, the only way he wouldn't get a full pair is with the green pair. That is where the 11/13 comes in, as two of the socks are green, making it not a full pair. But since he has 3 more black socks, 5 more white socks, and 3 more grey socks, when you add those together you get 11
5+3+3=11
Hope I helped!
Answer:
x = 1178 games
Step-by-step explanation:
Let the number of games = x
Let the total cost = Tc
Let the total revenue = Tr
Given the following data;
Investment = $10,000
Cost of each game = $1.50
Selling cost = $9.99
Total cost, Tc = (Cost of each game * Number of games) + Investment
Tc = 1.50x + 10000
Total revenue, Tr = Selling cost * Number of games
Tr = 9.99x
Breakeven point is when total cost is equal to total revenue;
Tc = Tr
x = 1177.86 ≈ 1178 games.
<em>Therefore, the number of games that must be sold before the business breaks even is 1178 games. </em>