Answer:
The length of the unknown sides of the triangles are as follows:
CD = 10√2
AC = 10√2
BC = 10
AB = 10
ΔACD is a right angle triangle. Therefore, Pythagoras theorem can be used to find the sides of the triangle.
c² = a² + b²
where
c = hypotenuse side = AD = 20
a and b are the other 2 legs
lets use trigonometric ratio to find CD,
cos 45 = adjacent / hypotenuse
cos 45 = CD / 20
CD = 1 / √2 × 20
CD = 20 / √2 = 20√2 / 2 = 10√2
20² - (10√2)² = AC²
400 - 100(2) = AC²
AC² = 200
AC = √200 = 10√2
ΔABC is a right angle triangle too. Therefore,
AB² + BC² = AC²
Using trigonometric ratio,
cos 45 = BC / 10√2
BC = 10√2 × cos 45
BC = 10√2 × 1 / √2
BC = 10√2 / √2 = 10
(10√2)² - 10² = AB²
200 - 100 = AB²
AB² = 100
AB = 10
Step-by-step explanation:
Answer would be 24 hope this is right
Answer:
y = -2x + 4
Step-by-step explanation:
Slope: (4-2)/5-1) = 2/4 = 1/2
Slope of the perpendicular line: -2
y-intercept: 2 - (-2)(1) = 4
Answer:
Step-by-step explanation:
![\sf 2x + 4(7-x) \\\\Resolving \ Parenthesis\\\\2x + 28-4x \\\\Combining\ like\ terms\\\\2x-4x +28\\\\-2x + 28\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%202x%20%2B%204%287-x%29%20%20%5C%5C%5C%5CResolving%20%5C%20Parenthesis%5C%5C%5C%5C2x%20%2B%2028-4x%20%5C%5C%5C%5CCombining%5C%20like%5C%20terms%5C%5C%5C%5C2x-4x%20%2B28%5C%5C%5C%5C-2x%20%2B%2028%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
![\sf \\12x-(4+2x)\\\\12x-4-2x\\\\Combining \ like \ terms\\\\12x-2x - 4\\\\10x-4 \\\\\rule[22]{225}{2} \\2(10-x)+3(12-x) \\\\Resolving \ Parenthesis\\\\20-2x + 36 -3x\\\\Combining \ like \ terms\\\\20+36 -2x-3x\\\\56 - 5x \\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20%5C%5C12x-%284%2B2x%29%5C%5C%5C%5C12x-4-2x%5C%5C%5C%5CCombining%20%5C%20like%20%5C%20terms%5C%5C%5C%5C12x-2x%20-%204%5C%5C%5C%5C10x-4%20%5C%5C%5C%5C%5Crule%5B22%5D%7B225%7D%7B2%7D%20%5C%5C2%2810-x%29%2B3%2812-x%29%20%5C%5C%5C%5CResolving%20%5C%20Parenthesis%5C%5C%5C%5C20-2x%20%2B%2036%20-3x%5C%5C%5C%5CCombining%20%5C%20like%20%5C%20terms%5C%5C%5C%5C20%2B36%20-2x-3x%5C%5C%5C%5C56%20-%205x%20%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
![\sf 7(x-1)-6(x+1)\\\\Resolving \ Parethesis\\\\7x-7-6x-6\\\\Combining \ like \ terms\\\\7x-6x-7-6\\\\x - 13\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%207%28x-1%29-6%28x%2B1%29%5C%5C%5C%5CResolving%20%5C%20Parethesis%5C%5C%5C%5C7x-7-6x-6%5C%5C%5C%5CCombining%20%5C%20like%20%5C%20terms%5C%5C%5C%5C7x-6x-7-6%5C%5C%5C%5Cx%20-%2013%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
~AnonymousHelper1807
