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Lady_Fox [76]
3 years ago
11

Lola was hiking 670 feet above sea level Dan was to 720 feet below her what was Dan’s elevation

Mathematics
1 answer:
Lesechka [4]3 years ago
8 0

Answer:

-50

Step-by-step explanation:

Dan's elevation is -50 feet below sea level. If Lola is at an elevation of 670 feet and Dan is 720 feet below her, you need to subtract; 670 - 720. This would get you to -50 feet which is Dan's elevation. Hope this helps!

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worty [1.4K]
Cos x = 15÷17
because cos is adjacent side over hypotenuse.
6 0
3 years ago
Please answer it correctly and please show work please help me if it’s correct I will mark you brainliest
Eva8 [605]

Answer:

210 hours

Step-by-step explanation:

<u>Step 1:  Make an expression</u>

(2/3 * 1575) / 5

<u>Step 2:  Multiply</u>

(2/3 * 1575)/5

(1050) / 5

<u>Step 3:  Divide</u>

(1050) / 5

210 hours

Answer:  210 hours

8 0
3 years ago
Which equation is equivalent to log Subscript 3 Baseline (x + 5) = 2?
adell [148]

Answer:

The correct option is right-bracket squared 3 squared =x+5

Step-by-step explanation:

The equation is \log _{3}(x+5)=2

Option a: \log _{3}(x+5)=3^{2}

This is not possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option a is not equivalent to \log _{3}(x+5)=2

Option b: \log _{3}(x+5)=2^{3}

This is not possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option b is not equivalent to \log _{3}(x+5)=2

Option c: x+5=3^{2}

This is possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option c is equivalent to \log _{3}(x+5)=2

Option b: x+5=2^{3}

This is not possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option b is not equivalent to \log _{3}(x+5)=2

Thus, the correct option is c: x+5=3^{2}

Hence, the equation x+5=3^{2} is equivalent to \log _{3}(x+5)=2

8 0
3 years ago
Which of the following points is a solution of y &gt; Ixl + 5?
Step2247 [10]

Answer:

B. (1,7)

Step-by-step explanation:

We can substitute the x and y values of each coordinate into the inequality and test if they work.

Let's start with A, 5 being y and 0 being x .

5 > |0|+5\\5> 0+5\\5 > 5

5 IS NOT greater than 5, they are the exact same, so A is out.

Let's try B, 1 being x and 7 being y.

7 > |1| + 5\\7 > 1 + 5\\7 > 6

7 IS greater than 6, so B. (1,7) does work for this inequality!

Let's do C for fun, when 7 is x and 1 is y.

1 > |7| + 5\\1>7+5\\1>12

1 IS NOT greater than 12, it is quite less than 12, so C doesn't work.

Therefore B. (1,7) works for the inequality of y > |x|+5.

Hope this helped!

7 0
3 years ago
What is the area of an isosceles triangle whose equal sides 5 cm and base side 6 cm​
zaharov [31]

Answer:

12 cm^2

Step-by-step explanation:

6 0
3 years ago
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