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s344n2d4d5 [400]
3 years ago
7

*PLS HELP* *ILL GIVE YOU BRAINYLIEST*

Mathematics
2 answers:
fredd [130]3 years ago
6 0

Answer:

-22/7 or -3.142857

Step-by-step explanation:

I can't type the explanation out hence the picture.

sdas [7]3 years ago
3 0

Answer:

22/-7

Step-by-step explanation:

Use Keep-Change-Flip for a question like this.

KEEP the 6/-7 exact the same. Keep it; don't do anything to it.

CHANGE the fraction bar which is a symbol for division to a Times

FLIP the 3/11 over and you get 11/3.

So when you Keep-Change-Flip, you then get

6/-7 × 11/3

When you multiply fraction times a fraction, you just multiply straight across: top×top and bottom×bottom.

You could cancel the 6 with the 3 below and leave a 2 up top.

So you get 6×11 on top and -7×3 on the bottom and after cancelling

2×11 / -7

= 22/-7

This is the same as -22/7 which looks nicer or

-3 1/7 which is a mixed number both of which are equivalent to the answer we found and have the same value and so are also correct answers.

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If a sample of gold were reduced to the smallest possible particles of pure gold, which statement would most accurately describe
yuradex [85]

Answer:

The sample would be reduced to atoms of gold.

Reason: All things are made up of atoms.

3 0
3 years ago
Read 2 more answers
Can y’all help me on this ? I kinda forgot how to do this-
Mashutka [201]
Answer: 62

Do you need an explanation?
7 0
3 years ago
Given f(x) =17 -x2 what is the average rate of change in f(x) over the interval [1,5]
Artist 52 [7]
By definition <span>the average rate of change is given by:
 </span>AVR =  \frac{f(x2) - f(x1)}{x2-x1}
 <span>We have the following function:
 </span>f(x) =17 - x^2
 We evaluate the function for the given interval:
 For X = 1:
 f(1) =17 - 1^2
 f(1) =17 - 1
 f(1) =16
 For X = 5:
 f(5) =17 - 5^2
 f(5) =17 - 25
 f(5) =-8
 Then, replacing values we have:
 AVR = \frac{-8 - 16}{5-1}
 AVR = \frac{-24}{4}
 AVR = -6
 Answer:
 <span>the average rate of change in f(x) over the interval [1,5] is:
 </span>AVR = -6


6 0
4 years ago
How to solve this system of equation 3x + y= 17 and 4x + 2 y = 20
lana66690 [7]
<span>3x + y= 17        (a)
4x + 2 y = 20    (b)

Multiply (a) by 2:

6x + 2y = 34   (a)
4x + 2y = 20   (b)

make:   (a) - (b)

2x = 14 -----> x =7

-------------------------------

Replace the value of x = 7 in one of anterior equation:

</span>3x + y= 17  
3 x 7 + y = 17
21 + y = 17
y = 17 - 21
y = -4
4 0
3 years ago
Element X decays radioactively with a half life of 11 minutes. If there are 870 grams of Element X, how long, to the nearest ten
serg [7]

Answer:

It would take 27.5 minutes the element to decay to 154 grams.

Step-by-step explanation:

The decay equation:

\frac {dN}{dt}\propto -N

\Rightarrow \R\frac {dN}{dt}=-\lambda N

\Rightarrow \frac {dN}N=-\lambda  dt

Integrating both sides

\Rightarrow \int \frac {dN}N=\int-\lambda  dt

\Rightarrow ln|N|=-\lambda  t+c

When t=0, N=N_0 = initial amount

ln|N_0|=-\lambda  .0+c

\Rightarrow c=ln|N_0|

ln|N|=-\lambda t+ln|N_0|

\Rightarrow ln|N|-ln|N_0|=-\lambda t

\Rightarrow ln|\frac{N}{N_0}|=-\lambda t

Decay equation:              

                    ln|\frac{N}{N_0}|=-\lambda t

Given that, the half life of of element X is 11 minutes.

For half life, N=\frac12  N_0,  t= 11 min.

ln|\frac{N}{N_0}|=-\lambda t

\Rightarrow ln|\frac{\frac12N_0}{N_0}|=-\lambda . 11

\Rightarrow ln|\frac12}|=-\lambda . 11

\Rightarrow -\lambda . 11=ln|\frac12}|

\Rightarrow \lambda =\frac{ln|\frac12|}{-11}

\Rightarrow \lambda =\frac{ln|2|}{11}                [ ln|\frac12|=ln|1|-ln|2|=-ln|2| , since ln|1|=0]

N=154 grams, N_0 = 870 grams, t=?

ln|\frac{N}{N_0}|=-\lambda t

\Rightarrow ln|\frac{154}{870}|=-\frac{ln|2|}{11}.t

\Rightarrow t= \frac{ln|\frac{154}{870}|\times 11}{-ln|2|}

      =27.5 minutes

It would take 27.5 minutes the element to decay to 154 grams.

5 0
3 years ago
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