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Nesterboy [21]
3 years ago
8

a dwarf sea horse swims at a rate of 54.68 feet per hour. convert this speed to inches per minute. the speed is ____ inches per

minute.
Mathematics
1 answer:
ella [17]3 years ago
3 0
10.936
54.68*12=656.16
656.16/60=10.936
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There are 40 students in a class.
VashaNatasha [74]

Answer:

6 boys have brown hair.

Step-by-step explanation:

40*0.6 = 24 boys in the class.

24 * 0.25 = 6 boys have brown hair.

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3 years ago
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These are the first sentences in the short story, "The Gift of the Magi," by O. Henry: "One dollar and eighty-seven cents. That
Liula [17]
$1.87

60 cents in pennies = $.60

Each quarter is $.25, each dime is $.10, and each nickel is $.05.

1.87=q*.25+d*.10+n*.05+.60
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4 years ago
Given g(x)=sqrt x-4 and h(x)=2x-8 what is (g(h(10))<br> HELP ME I AM .3 POINTS AWAY FROM PASSING.
Whitepunk [10]

<span><span>The answer (<span>g<span>(x)</span></span>)</span>=x−7</span>

<span><span>g<span>(<span>f<span>(x)</span></span>)</span></span>=<span>√<span><span>x2</span>−7</span></span></span>

Explanation:

Put g inside f to find <span>f<span>(<span>g<span>(x)</span></span>)</span></span>

<span><span>f<span>(x)</span></span>=<span>x2</span>−4</span>

<span><span>g<span>(x)</span></span>=<span>√<span>x−3</span></span></span>

<span><span>f<span>(<span>g<span>(x)</span></span>)</span></span>=<span><span>(<span>√<span>x−3</span></span>)</span>2</span>−4</span>

<span><span>f<span>(<span>g<span>(x)</span></span>)</span></span>=x−3−4</span>

<span><span>f<span>(<span>g<span>(x)</span></span>)</span></span>=x−7</span>

Put f inside g to find <span>g<span>(<span>f<span>(x)</span></span>)</span></span>

<span><span>g<span>(x)</span></span>=<span>√<span>x−3</span></span></span>

<span><span>f<span>(x)</span></span>=<span><span>x2</span>−4</span></span>

<span><span>g<span>(<span>f<span>(x)</span></span>)</span></span>=<span>√<span><span><span>x2</span>−4</span>−3</span></span></span>

<span><span>g<span>(<span>f<span>(x)</span></span>)</span></span>=<span>√<span><span>x2</span>−7</span></span></span>:

The answers are <span><span>f<span>(<span>g<span>(x)</span></span>)</span></span>=x−7</span> 
and <span><span>g<span>(<span>f<span>(x)</span></span>)</span></span>=<span>√<span><span>x2</span>−7</span></span></span>

Explanation:

This is a composition of functions.

<span><span>f<span>(x)</span></span>=<span>x2</span>−4</span>

<span><span>g<span>(x)</span></span>=<span>√<span>x−3</span></span></span>

<span>fo<span>g<span>(x)</span></span>=<span>f<span>(<span>g<span>(x)</span></span>)</span></span>=<span>f<span>(<span>√<span>x−3</span></span>)</span></span>=<span><span>(<span>√<span>x−3</span></span>)</span>2</span>−4</span>

<span>=x−3−4=x−7</span>

And

<span>go<span>f<span>(x)</span></span>=<span>g<span>(<span>f<span>(x)</span></span>)</span></span>=<span>g<span>(<span>x2</span>−4)</span></span>=<span>√<span><span>(<span>x2</span>−4)</span>−3</span></span></span>

<span>=<span>√<span><span>x2</span>−4−3</span></span>=<span>√<span><span>x2</span>−7</span></span></span>

You can see that

<span><span>f<span>(<span>g<span>(x)</span></span>)</span></span>≠</span>g(f(x))


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4 years ago
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A model for the following problem 5 times 3
harkovskaia [24]
5×3=15 because 5 plus five plus five equals 15 if you add it together correctly 
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3 years ago
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Diana paints 150 fence posts and chuck paints 130 fence posts. Diana paints 10 more fence posts than chuck. How many fence posts
statuscvo [17]

Complete Question

The  complete question is shown on the first uploaded image

Answer:

Step-by-step explanation:

From the question we are told that

  The  relationship is  \frac{150 }{d}   = \frac{130}{c}

   The number of fence post painted by chuck is  l = 130

    The number of fence post painted by Diana  is k =  150

    can paint 10 fences more than chuck  so let say the  of fence painted in an hour by chuck is g

     Then  the number of fence post painted by Diana in one hour is

          f =  g+ 10

 So

       \frac{150 }{ g + 10 }   = \frac{130}{g}

       130 g  + 1300 =  150g

        g =  65 \  m

5 0
4 years ago
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