3 years ago

Y=sech(tan‐¹x) find the derivative

Mathematics

1 answer:

Klio2033 [76]3 years ago

8 0

Recall that

d/dx sech(x) = - sech(x) tanh(x)

d/dx tan⁻¹(x) = 1/(1 + x²)

Then by the chain rule,

dy/dx = - sech(x) tanh(x) / (1 + x²)

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Y=sech(tan‐¹x) find the derivative ​

Y=sech(tan‐¹x) find the derivative