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kotykmax [81]
3 years ago
7

Sinx + cosx= 1 then find the value of x

Mathematics
1 answer:
Kobotan [32]3 years ago
4 0
   1√2sinx+1√2cosx=1√2.

This can be written as

cos(x−π4)=cos(π4)

The general solution of this equation ls

x−.π4=2nπ±π4,n=0,±1,±2,...,

So, x=2nπandx=(4n+1)π2,n=0,±1,±2,±3....

 ANSWER: x=2nπandx=(4n+1)π2,n=0,±1,±2,±3....


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