3 years ago

Sinx + cosx= 1 then find the value of x

1 answer:

4 0

$1√2sinx+1√2cosx=1√2.

This can be written as

cos(x−π4)=cos(π4)

The general solution of this equation ls

x−.π4=2nπ±π4,n=0,±1,±2,...,

So, x=2nπandx=(4n+1)π2,n=0,±1,±2,±3....

 ANSWER: x=2nπandx=(4n+1)π2,n=0,±1,±2,±3....$

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3 years ago

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nikitadnepr [17]

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