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2 years ago

Nomenclature of this compoundspammers will be reported

Chemistry

1 answer:

kogti [31]2 years ago

7 0

Answer:

Nomenclature is the process of naming chemical compounds with different names so that they can be easily identified as separate chemicals. ... For example, organic compounds include molecules with carbon rings and/or chains with hydrogen atoms (see picture below).01-Jul-2014

Nomenclature: Iron (II) Chloride

Compound: FeCl2

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Consider the reaction between ozone and a metal cation, m2+, to form the metal oxide, mo2, and dioxygen: o3 + m2+(aq) + h2o(l) →

Mandarinka [93]

O3 + M2+(aq) + H2O(l) => O2(g) + MO2(s) + 2 H+
Eo(cell) = Eo(O3/O2) - Eo(MO2/M2+)
0.44 = 2.07 - Eo(MO2/M2+)
Eo(MO2/M2+) = 1.59 V

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4 years ago

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Who placed all the elements in the right place according to their properties

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Dmitri Mendeleev Was the name of the guy you where looking for

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3 years ago

Two gas-filled tanks have the same volume, temperature, and pressure. They are identical in every way except that one is filled

Tems11 [23]

Answer:

The tank with O₂ weighs more.

Explanation:

We can find the mass of gas using the ideal gas equation.

$P.V=n.R.T=\frac{m}{M} .R.T\\m=\frac{P.V.M}{R.T}$

Considering the pressure (P), volume (V), temperature (T) and ideal gas constant (R) are the same, we can establish that:

m ∝ M

The mass is directly proportional to the molar mass. The molar mass of O₂ (32 g/mol) is higher than the molar mass of N₂ (28 g/mol). Therefore, the tank with O₂ weighs more.

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3 years ago

The charge of single electron

irga5000 [103]

The answer is B.

plz mark me as brainliest. i really need it.

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4 years ago

a sample of hydrogen gas (h2) is mixed with water vapor (h2o (g)). the make sure has a total pressure of 811 torr, and the water

Alborosie

Answer:

$n=0.430molH_2$

Explanation:

Hello!

In this case, considering the partial Dalton's law of partial pressures, we can notice that the total pressure equals the pressure of steam and the pressure of hydrogen, which can be determined as shown below:

$p_T=p_H+p_w\\\\p_H=811torr-12torr=799torr*\frac{1atm}{760torr}\\\\p_H=1.05atm$

Thus, by using the ideal gas law, we can compute the moles of hydrogen as shown below:

$PV=nRT\\\\n= \frac{PV}{RT}=\frac{1.05atm*10.0L}{0.082\frac{atm*L}{mol*K}*298K}\\\\n=0.430molH_2$

Best regards!

6 0

3 years ago

Nomenclature of this compoundspammers will be reported​

Nomenclature of this compoundspammers will be reported