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Marta_Voda [28]
3 years ago
7

3. What causes hydrogen bonding?

Chemistry
2 answers:
velikii [3]3 years ago
7 0

Answer:

The variation in attraction of some atoms causes hydrogen bonding

Explanation:

Hydrogen bonding is caused by the tendency of some atoms in molecules to attract electrons more than their accompanying atom.

This gives the molecule a permanent dipole moment, it makes it polar, so it acts like a magnet and attracts the opposite end of other polar molecules.

What is hydrogen bonding?

A hydrogen bond is a partial intermolecular bonding interaction between a lone pair on an electron rich donor atom.

Fudgin [204]3 years ago
5 0
Hydrogen bonding occurs between a hydrogen atom and an electronegative atom (e.g., oxygen, fluorine, chlorine). The bond is weaker than an ionic bond or a covalent bond, but stronger than van der Waals forces (5 to 30 kJ/mol). A hydrogen bond is classified as a type of weak chemical bond.
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Montano1993 [528]

Answer:

C

Explanation:

In thermodynamics, a exothermic system looses heat to the surroundings while an endothermic system absorbs heat from the surroundings.

A system is a part the universe marked off by a specified boundary. The contents of the cup constitutes the system in this case.

The region of space outside the system is called the surroundings. Hence everything outside the cup constitutes the surroundings.

7 0
3 years ago
What is Heterogeneous? And an example. What is Homogeneous? And an example. I just need those, thanks
Sedbober [7]
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7 0
3 years ago
A 10.0 g sample of propane, C3H8, was combusted in a constant-volume bomb calorimeter. The total heat capacity of the bomb calor
Liono4ka [1.6K]

Answer:

83ºC

Explanation:

A bomb calorimeter is an instrument used to measure the heat that release or absorb a particular reaction.

The reaction of combustion of propane is:

C₃H₈ +  5O₂ → 3 CO₂ + 4 H₂O ΔH = -2222kJ/mol

<em>1 mole of propane release 2222kJ</em>

10.0g of propane (Molar mass: 44.1g/mol).

10.0g ₓ (1mol/ 44.1g) = <em>0.227 moles of C₃H₈</em>

If 1 mole of propane release 2222kJ, 0.227moles will release (Release because molar heat is < 0):

0.227 moles of C₃H₈ ₓ (2222kJ / mol) = 504kJ.

Our calorimeter has a constant of 8.0kJ/ºC, that means if there are released 8.0kJ, the bomb calorimeter will increase its temperature in 1ºC. As there are released 504kJ:

504kJ ₓ (1ºC / 8.0kJ) = 63ºC will increase the temperature in the bomb calorimeter.

As initial temperature was 20ºC, final temperature will be:

<h2>83ºC</h2>
8 0
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3 years ago
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kicyunya [14]

Answer:

first modern?

Explanation:

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