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Furkat [3]
2 years ago
14

What is the volume of 2.1 moles of chlorine gas (Cl2) at standard temperature and pressure (STP)?

Chemistry
1 answer:
uysha [10]2 years ago
5 0
Given:
<span> 2.1 moles of chlorine gas (Cl2) at standard temperature and pressure (STP)
Required:
volume of CL2
Solution:
Use the ideal gas law
PV = nRT
V = nRT/P
V = (2.1 moles Cl2) (0.08203 L - atm / mol - K) (273K) / (1 atm)
V = 47 L</span>
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Hydrogen may not be advantagous as a fuel because-------
sergeinik [125]

Answer:

Hydrogen may not be advantageous as a fuel because...

- Its expensive

- Its difficult to store

- Its highly flammable

- Its dependent on fossil fuels

Explanation:

Its expensive - Not only is hydrogen gas expensive, but it also takes a lot of work to free from other elements. It is both expensive and time-consuming to produce.

Its difficult to store - Moving hydrogen is not an easy task. Moving anything more than small amounts of hydrogen was also very expensive, making it impractical.

Its highly flammable - When exposed to the atmosphere, hydrogen could potentially form explosive mixtures.

Its dependent on fossil fuels - Hydrogen energy itself is renewable. However, the process of separating it from oxygen uses non-renewable sources such as coal and oil.

~Hope this Helps!~

7 0
3 years ago
A cube has sides that are 0.03 m . What is the volume of the cube in liters?
Marizza181 [45]

Answer:

0.027 litres

Explanation:

volume of cube = length × base area

volume of cube = 0.03m ×( 0.03m × 0.03m )

volume of cube = 0.03m × ( 0.0009m^2 )

volume of cube = 0.000027m^3

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8 0
2 years ago
If a sample of HF gas at 694.9 mmHg has a volume of 3.463 Land the volume is changed to 5.887 L, then what will be the new press
VARVARA [1.3K]

Answer:

\large \boxed{\text{381.7 mmHg}}

Explanation:

Data:

p₁ = 694.9 mmHg; V₁ = 3.463 L

p₂ = ?;                     V₂ = 5.887 L

Calculation:

\begin{array}{rcl}p_{1}V_{1} & = & p_{2}V_{2}\\\text{648.9 mmHg} \times \text{3.463 L} & = & p_{2} \times\text{5.887 L}\\\text{2247.1 mmHg} & = & 5.887p_{2}\\p_{2} & = & \dfrac{\text{2247.1 mmHg}}{5.887}\\\\& = &\textbf{381.7 mmHg}\\\end{array}\\\text{The new pressure of the gas is $\large \boxed{\textbf{381.7 mmHg}}$}

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3 years ago
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Explanation:

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