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In a school the number of girls is more than twice the number of boys. If the school has 650 students find the greatest number o

Leya [2.2K]

Answer:

750

Step-by-step explanation:

because if the has 650 students and it is the greatest number

8 0

3 years ago

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Is the sequence geometric? if so, identify the common ratio 1/5,2/15,4/45,8/135,16/405,...

Romashka-Z-Leto [24]

So have the sequence: $\frac{1}{5} , \frac{2}{15} , \frac{4}{45} , \frac{8}{135} , \frac{16}{145} ,...$
To check if the sequence is geometric, we are going to find its common ratio; to do it we are going to use the formula: $r= \frac{a_{n} }{a_{n-1}}$
where
$r$ is the common ratio
$a_{n}$ is the current term in the sequence
$a_{n-1}$ is the previous term in the sequence
In other words we are going to divide the current term by the previous term a few times, and we will to check if that ratio is the same:

For $a_{n}= \frac{2}{15}$ and $a_{n-1}= \frac{1}{5}$ :
$r= \frac{ \frac{2}{15} }{ \frac{1}{5} }$
$r= \frac{2}{3}$

For $a_{n}= \frac{4}{45}$ and $a_{n-1}= \frac{2}{15}$ :
$r= \frac{ \frac{4}{45} }{ \frac{2}{15} }$
$r= \frac{2}{3}$

For $a_{n}= \frac{8}{135}$ and $a_{n-1}= \frac{4}{45}$ :
$r= \frac{ \frac{8}{135} }{ \frac{4}{45} }$
$r= \frac{2}{3}$
As you can see, we have a common ratio!

We can conclude that our sequence is a geometric sequence and its common ratio is $\frac{2}{3}$

7 0

3 years ago

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Find the values of the measures shown when each value in the data set increases by 25. Mean: 109 Median: 104 Mode: 96 Range: 45

Vikki [24]

Answer:

The new values are as follows:

Mean: 134

Median: 129

Mode: 121

Range=45

Standard Deviation=3.6

Step-by-step explanation:

When a k real number is added to all the elements of the dataset, the new measures of center (mean, median, and mode) are simply found by adding the value k to the previous values. Thus

$Mean_{new}=Mean_{old}+k$

Here $Mean_{old}$ is 109 and k is 25 thus

$Mean_{new}=Mean_{old}+k\\Mean_{new}=109+25\\Mean_{new}=134$

Similarly

$Median_{new}=Median_{old}+k$

Here $Median_{old}$ is 104 and k is 25 thus

$Median_{new}=Median_{old}+k\\Median_{new}=104+25\\Median_{new}=129$

Also

$Mode_{new}=Mode_{old}+k$

Here $Mode_{old}$ is 96 and k is 25 thus

$Mode_{new}=Mode_{old}+k\\Mode_{new}=96+25\\Mode_{new}=121$

When a k real number is added to all the elements of the dataset, the new measures of variation (range and standard deviation) remain the same thus.

$Range_{new}=Range_{old}\\Range_{new}=45$

Similarly

$Standard\ Deviation_{new}=Standard\ Deviation_{old}\\Standard\ Deviation_{new}=3.6$

So the new values of mean, median, mode, range, and standard deviation are 134, 129, 121, 45, and 3.6 respectively.

4 0

3 years ago

Yo lets play among us!!

seropon [69]

Answer:

yass dude lets go

4 0

3 years ago

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What is the percent of change from 2000 to 200

Kamila [148]

Answer: 90% decrease

Step-by-step explanation: First determine whether the number is increasing or decreasing. Since it changes from 2,000 to 200, it's going down so it's decreasing.

Now to find the percent decrease, we divide the

amount of change by the original number.

The <em>amount of change</em> is the difference between the two numbers

which in this case is 2,000 - 200 and the original number is 2,000.

$So$ $we$ $have$ $\frac{2,000 - 200}{2,000}$ .