Answer:
1/a²⁷
Step-by-step explanation:
Given: 
We know that when the bases are same the powers can be added. i.,e.,
(xᵃ)ᵇ = x ⁽ᵃ ⁺ ᵇ⁾
⇒ 
Also, 
This is nothing but,
.
Note that
cannot be zero here. The condition is provided in the question as well.
Answer:
x > 3
Step-by-step explanation:
___________________
Answer:
A. (-7 -2)
Step-by-step explanation:
You can eliminate y by multiplying the first equation by 7 and subtracting 6 times the second equation:
7(-3x +6y) -6(5x +7y) = 7(9) -6(-49)
-21x +42y -30x -42y = 63 +294 . . . . eliminate parentheses
-51x = 357 . . . . . . . . collect terms
x = -7 . . . . . . . divide by -51. This matches answer choice A.