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Len [333]
3 years ago
5

A can in the shape of a right cylinder is filled with 10W-40 oil. The weight of 10W-40 oil is 0.857 gram per cubic centimeter. I

f the cylinder has a radius of length 6 cm and a height of 10 cm, calculate the weight of the oil (in grams) in the can. Round your answer to the nearest tenth.
Mathematics
1 answer:
Leya [2.2K]3 years ago
5 0
To solve this, we have to find the volume of the cylinder first.  The formula to be used is V =  \pi  r^{2} h

Given:V= ?r= 6cmh= 10cm
Solution:V =  \pi  r^{2} h
V= (3.14)(6cm)^{2} x 10cmV= (3.14)(36cm^{2}) x 10cmV= (113.04cm^{2}) x 10cmV= 1130.4cm^3
Finding the volume of the cylinder, we can now solve what the weight of the oil is.  Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.
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Answer:

x³ - 3x² + 5x - 3 / x² - 2

Step-by-step explanation:

Given in the question,

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Formula for the height of prism

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plug values in the formula

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We will do long division

           x - 1

          ----------------------------

x² - 2 | x³ - 3x² + 5x - 3

           x³ - 2x²

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                  ----------------------

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The remainder indicates that x³ - 3x² + 5x - 3 is not divisible by x² - 2, and that means that you cannot find the exact height.

6 0
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Answer:

- 2

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [ a, b ] = [ 3, 7 ] and from the graph

f(b) = f(7) = 2

f(a) = f(3) = 10, hence

average rate of change = \frac{2-10}{7-3} = \frac{-8}{4} = - 2

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