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Len [333]
2 years ago
5

A can in the shape of a right cylinder is filled with 10W-40 oil. The weight of 10W-40 oil is 0.857 gram per cubic centimeter. I

f the cylinder has a radius of length 6 cm and a height of 10 cm, calculate the weight of the oil (in grams) in the can. Round your answer to the nearest tenth.
Mathematics
1 answer:
Leya [2.2K]2 years ago
5 0
To solve this, we have to find the volume of the cylinder first.  The formula to be used is V =  \pi  r^{2} h

Given:V= ?r= 6cmh= 10cm
Solution:V =  \pi  r^{2} h
V= (3.14)(6cm)^{2} x 10cmV= (3.14)(36cm^{2}) x 10cmV= (113.04cm^{2}) x 10cmV= 1130.4cm^3
Finding the volume of the cylinder, we can now solve what the weight of the oil is.  Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.
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Step-by-step explanation:

Subtraction

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2 years ago
given abc with a(-4 -2), b(4,4), and c(18,-8). write the equation of the line that contains the altitude that passes through b i
Tresset [83]

check the picture below.

so red line of BD is perpendicular to AC, hmmmm let's firstly find the slope of AC, bearing in mind that perpendicular lines have <u>negative reciprocal</u> slopes.


\bf A(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-2})\qquad C(\stackrel{x_2}{18}~,~\stackrel{y_2}{-8}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-8-(-2)}{18-(-4)}\implies \cfrac{-8+2}{18+4} \\\\\\ \cfrac{-6}{22}\implies -\cfrac{3}{11} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{3}{11}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{11}{3}}\qquad \stackrel{negative~reciprocal}{\cfrac{11}{3}}}\impliedby \textit{BD's slope}


so we're really looking  for the equation of a line whose slope is 11/3 and runs through B(4,4).  Keeping in mind that

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient


\bf B(\stackrel{x_1}{4}~,~\stackrel{y_1}{4})~\hspace{10em} slope = m\implies \cfrac{11}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-4=\cfrac{11}{3}(x-4)


\bf \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}\textit{ to do away with the denominators}}{3(y-4)=3\left( \cfrac{11}{3}(x-4) \right)\implies 3y-12=11(x-4)} \\\\\\ 3y-12=11x-44\implies 3y=11x-32 \\\\\\ -11x+3y=-32\implies \blacktriangleright 11x - 3y= 32\blacktriangleleft

4 0
2 years ago
AOV is a right angle and the ratio AOB: BOC= 2:3 what is the size of angle BOC ?
seraphim [82]
A right angle = 90 degree
BOC = 3/5 of the right angle
= 3/5 x 90
= 54 degree
7 0
2 years ago
Micheal has 1/2 of a yard of fabric to make book covers. Each book cover is made from 1/8 of a yard of fabric. How many book cov
lesantik [10]

Answer:

4

Step-by-step explanation:

\frac{1}{2} ÷ \frac{1}{8} = 4

4 0
3 years ago
Need help with this !
gulaghasi [49]

Answer:

(-2,14) Hope this helps! Have a great day!!!

7 0
3 years ago
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