For the fulcrum to balance, the product of weight and distance on both sides of the fulcrum must be the same.
Let d1= x. since total distance is 12, we can write d2 = 12 - x
for the fulcrum to balance:
60x = 50(12 - x)
60x = 600 - 50x
110x = 600
x = 5.45
Thus, d1= 5.45
and
d2= 12 - d1 = 12 - 5.45 = 6.55
d1 = 5.45
d2 = 6.55
Answer:
$90
Step-by-step explanation:
To solve this problem, you simply multiply $60 by 50%. Remember to change 50% into its decimal form (50% -> 0.5).
60 x 0.5 = 30
Now we add 30 to the original price of $60 to get our final answer.
$60 + 30 = $90
Box 1) (LxW) 20x6=120
box 2) (LxW) 15x4=60
box 1 cost) (size of box x price of box) 120x1.25=150
box 2 cost) (size of box x price of box) 60x1.25=75
subtract 150 and 75 to get 75
answer: the company is saving $75 by choosing to make 50 of box 2 instead of 50 of box 1
hope this makes sense comment if you need more explanation
L = 2W
P = 2L + 2W
Plug 2W in for L.
54 = 2(2W) + 2W
54 = 4W + 2W
54 = 6W
Divide both sides by 6
W = 9
L = 2* 9
L = 18
A = L * W
A = 9 * 18
A = 162 units^2
The answer is 18. F(2) is saying that x is equal to 2. so where ever there is an x in the problem you should fill in 2 for. then all you have to do is type it into a graphing calculator and solve.
