Answer:
x = 4
Explanation:
Given the expression;
![\sqrt[]{x}-4\text{ = -2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7Bx%7D-4%5Ctext%7B%20%3D%20-2%7D)
Add 4 to both sides
![\begin{gathered} \sqrt[]{x}-4+4\text{ = -2+4} \\ \sqrt[]{x}=\text{ 2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Csqrt%5B%5D%7Bx%7D-4%2B4%5Ctext%7B%20%3D%20-2%2B4%7D%20%5C%5C%20%5Csqrt%5B%5D%7Bx%7D%3D%5Ctext%7B%202%7D%20%5Cend%7Bgathered%7D)
Square both sides
![\begin{gathered} (\sqrt[]{x})^2=2^2 \\ x\text{ = 4} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%28%5Csqrt%5B%5D%7Bx%7D%29%5E2%3D2%5E2%20%5C%5C%20x%5Ctext%7B%20%3D%204%7D%20%5Cend%7Bgathered%7D)
Hence the value of x is 4
This is a binomial distribution.
p = 0.71, q = 1 - p = 1 - 0.71 = 0.29, n = 20
P(x ≤ 19) =1 - P(x = 20) = 1- 20C20 x (0.71)^(20 - 20) x (0.29)^20 = 1 - 0.29^20 = 1 - 0 = 1
Step-by-step explanation:
Let's say R is the initial radius of the sphere, and r is the radius at time t.
The volume of the sphere at time t is:
V = 4/3 π r³
Taking derivative with respect to radius:
dV/dr = 4π r²
This is a maximum when r is a maximum, which is when r = R.
(dV/dr)max = 4π R²
This is 4 times the sphere's initial great circle area, but not the great circle circumference. The problem statement contains an error.
For this case we can have the following function:
r = f (t)
Where,
Independent variable is t.
Dependent variable is r.
To find the inverse we solve for the independent variable, that is, the data entry variable.
Answer:
FALSE
option B
