All categories

3 years ago

Please help hard math lots of points

Mathematics

2 answers:

marissa [1.9K]3 years ago

6 0

The equation y = -3|x|-1 describes the graph

hjlf3 years ago

4 0

Answer:

the answer would be d

Step-by-step explanation:

hope this helps:)

You might be interested in

710 pts;10% decrease

allochka39001 [22]

10%of 710 is 71

now we have 710-71=639

3 0

4 years ago

Find the area of the shaded regions below. Give your answer as a completely simplified exact value in terms of π (no approximati

Lera25 [3.4K]

Answer:

(36π -72) cm²

Step-by-step explanation:

The area of a segment that subtends arc α (in radians) is given by ...

A = (1/2)r²·(α - sin(α))

Here, you have r = 12 cm and α = π/2 radians, so the area of the segment is ...

A = (1/2)(12 cm)²·(π/2 -1) = (36π -72) cm²

4 0

3 years ago

Read 2 more answers

At what rate per annum does the compound interest of Rs 576 becomes to Rs 153 in 2 years

ArbitrLikvidat [17]

Answer:

The value of rate per annum is R = 12.5 %

Step-by-step explanation:

Principal amount = 576

Interest = 153

Amount after 2 years = 576 + 153 = 729

We know that

$A = P [1 + \frac{R}{100} ] ^{T}$

Put all the values in above equation

$729 = 576 [1 + \frac{R}{100} ]^{2}$

$\frac{27}{24} = 1 + \frac{R}{100}$

R = 12.5 %

This is the value of rate per annum.

4 0

3 years ago

−4x+7y+5= 0x−3y=−5 How many solutions does the system have?

seraphim [82]

{-4x+7y+5=-5
{0x-3y=-5 Solve the equation.

{-4x+7y+5=-5
{y=5/3 Substitute the value of y.

-4x+7(5/3)+5=-5 Plug in and solve.

x=65/12 You should get this answer.

Therefore: (x,y) = (65/12,5/3)

6 0

3 years ago

Sara has a stack of 8 plates, each plate is 0.5 inches tall and she is trying to wrap them as a gift.

AlekseyPX

Answer:

The plates will not fit into the box.

Step-by-step explanation:

Each plate is 0.5 inches tall; therefore, the stack of 8 plates will have a height of $0.5in*8 = 4inches$ .

Also, the diameter of the largest plate is 10 inches or has a radius of 5 inches, which matches the radius of the cylindrical box; therefore, we know that the stack of plates can fit into the base area of the cylindrical box.

What we want to figure out now is the height of the cylindrical box to see if it is greater than or equal to 4 inches—the height of the stack of plates.

The volume of a cylinder is $\pi R^2h$ , and since for our cylindrical box the volume is 150 cubic inches; therefore,

$\pi R^2h = 150in^3$

putting in $R = 5in$ and solving for height $h$ we get

$h = \dfrac{150in^3}{\pi (5)^2}$

$h = 1.91\: inches$ ,

which is not greater than 4 inches, which means the plates will not fit into the box since the height of the stack is greater than the height of the box.

5 0

3 years ago