A rectangular athletic field is twice as long as it is wide. If the perimeter of the athletic field is 90 yards, what are its di
1 answer:
You might be interested in
Answer:
(1) 4.09% of the New York City commutes are for less than 26 minutes.
(2) 14.32% are between 26 and 32 minutes.
(3) 54.23% are between 26 and 40 minutes.
Step-by-step explanation:
We are given that the longest one-way travel time is in New York City, where the mean time is 38.5 minutes.
Assume the distribution of travel times in New York City follows the normal probability distribution and the standard deviation is 7.2 minutes.
Let X = <u><em>travel times in New York City.</em></u>
So, X ~ Normal()
The z-score probability distribution for the normal distribution is given by;
Z = ~ N(0,1)
where, = population mean travel time = 38.5 minutes
= standard deviation = 7.2 minutes
(1) The percent of the New York City commutes that are less than 26 minutes is given by = P(X < 26 minutes)
P(X < 26 minutes) = P( <
) = P(Z < -1.74) = 1 - P(Z
1.74)
= 1 - 0.9591 = <u>0.0409</u> = 4.09%
The above probability is calculated by looking at the value of x = 1.74 in the z table which has an area of 0.9591.
(2) The percent of the New York City commutes that are between 26 and 32 minutes is given by = P(26 min < X < 32 min) = P(X < 32 min) - P(X 26 min)
P(X < 32 min) = P( <
) = P(Z < -0.90) = 1 - P(Z
0.90)
= 1 - 0.8159 = 0.1841
P(X 26 min) = P(
) = P(Z
-1.74) = 1 - P(Z < 1.74)
= 1 - 0.9591 = 0.0409
The above probability is calculated by looking at the value of x = 0.90 and x = 1.74 in the z table which has an area of 0.8159 and 0.881 respectively.
Therefore, P(26 min < X < 32 min) = 0.1841 - 0.0409 = <u>0.1432</u> or 14.32%.
(3) The percent of the New York City commutes that are between 26 and 40 minutes is given by = P(26 min < X < 40 min) = P(X < 40 min) - P(X 26 min)
P(X < 40 min) = P( <
) = P(Z < 0.21) = 0.5832
P(X 26 min) = P(
) = P(Z
-1.74) = 1 - P(Z < 1.74)
= 1 - 0.9591 = 0.0409
The above probability is calculated by looking at the value of x = 0.21 and x = 1.74 in the z table which has an area of 0.5832 and 0.881 respectively.
Therefore, P(26 min < X < 40 min) = 0.5832 - 0.0409 = <u>0.5423</u> or 54.23%
Answer:
The graph in the attached figure
Step-by-step explanation:
Let
x------> the number of fancy goldfish
y-----> the number of common goldfish
we know that
The linear equation that represent the situation is equal to
Isolate the variable y
To graph the line find the intercepts
The x-intercept is equal to the point ----> value of x when the value of y is equal to zero
The y-intercept is equal to the point ----> value of y when the value of x is equal to zero
Plot the points
The graph in the attached figure
The solution of the problem is all positive ordered pairs of whole numbers belong to the line
The possible solutions are
For ------>
For ------>
For ------>
For ------>
For ------>
For ------>
For ------>
The domain (number of fancy goldfish) is the interval--------->
The range (number of common goldfish) is the interval--------->
