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elixir [45]
4 years ago
12

Which of these experiments would make use of qualitative data?

Physics
2 answers:
Artyom0805 [142]4 years ago
8 0
The answer is A study of different surfaces to compare ability to repel water. Hope this helps!
FromTheMoon [43]4 years ago
4 0
I took the test your answer is B
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Walt ran 5 km in 25 minutes going east to what was his average velocity
goldenfox [79]

distance d = 5 km = 5 x 1000 m = 5000 m

time taken = 25 minute = 25 x 60 sec = 1500 sec

average velocity V = d/t

V = 5000/1500

V = 3.33 m/s towards east

3 0
4 years ago
Read 2 more answers
A solid conducting sphere with radius RR that carries positive charge QQ is concentric with a very thin insulating shell of radi
svetlana [45]

Answer:

E=0 at r < R;

E=\frac{1}{4\pi\epsilon}\frac{Q}{r^{2}} at 2R > r > R;

E=\frac{1}{4\pi\epsilon} \frac{2Q}{r^{2}} at r >= 2R

Explanation:

Since we have a spherically symmetric system of charged bodies, the best approach is to use Guass' Theorem which is given by,

\int {E} \, dA=\frac{Q_{enclosed}}{\epsilon} (integral over a closed surface)

where,

E = Electric field

Q_{enclosed} = charged enclosed within the closed surface

\epsilon = permittivity of free space

Now, looking at the system we can say that a sphere(concentric with the conducting and non-conducting spheres) would be the best choice of a Gaussian surface. Let the radius of the sphere be r .

at r < R,

Q_{enclosed} = 0 and hence E = 0 (since the sphere is conducting, all the charges get repelled towards the surface)

at 2R > r > R,

Q_{enclosed} = Q,

therefore,

E\times4\pi r^{2}=\frac{Q_{enclosed}}{\epsilon}      

(Since the system is spherically symmetric, E is constant at any given r and so we have taken it out of the integral. Also, the surface integral of a sphere gives us the area of a sphere which is equal to 4\pi r^{2})

or, E=\frac{1}{4\pi\epsilon}\frac{Q}{r^{2}}

at r >= 2R

Q_{enclosed} = 2Q

Hence, by similar calculations, we get,

E=\frac{1}{4\pi\epsilon} \frac{2Q}{r^{2}}

4 0
4 years ago
What happened to a apple's weigh as the plane rose up toward the sky?
uysha [10]

Okay, I don't know if this question is supposed to be a trick question or not. The weight of the apple does not change as the plane travels up the atmosphere, but the MASS changes. Weight doesn't change no matter what environment you're in, but the mass changes in different environments. In this case, the weight is constant but the mass is decreasing as you go higher up.
5 0
3 years ago
What is clean Cole technology
natima [27]
Technology that does not harm the environment (environmental friendly technology)
3 0
4 years ago
Lenses are often coated with magnesium fluoride (refractive index n = 1.38) to reduce reflections. How thick should the layer of
Valentin [98]

Answer: 99.64 nm (≅ 100 nm)

Explanation: In order to explain this problem we have to obtain destructive inteference from two waves that reflect in the film and lens surface so both waves have a λ/2 shift then we have to get a difference path (2L) equal to an odd number of the half wavelegth.

Then we have the following expression:

L=(m+1/2)* λ/(2*n2);  where n2 is the refractive index of the coating

for m=0 we have the minimum thickness for the coating

L=λ/(4*n2)=99.64 nm (≅ 100 nm)

6 0
3 years ago
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