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Alekssandra [29.7K]
2 years ago
15

"In a pure substance all the particles must be identical; therefore pure substances are composed only of elements." Do you agree

with this statement? Why or why not?
Physics
1 answer:
kenny6666 [7]2 years ago
6 0

I do not agree with the statement.
The "substance" can be a compound.  It's "pure"
as long as there's nothing else in it but its name.

'Pure' water is 100% H₂O with nothing else in it.
'Pure' table salt is 100% NaCl with nothing else in it.
'Pure' carbon dioxide is 100% CO₂ with nothing else in it.

These example substances are all compounds, not elements.
 
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The helicopter was deformed and destroyed in the _______ collision.
ASHA 777 [7]

There are two types of collision in physics which are named as elastic collision and inelastic collision.

Elastic collision is that type of collision in which both kinetic energy and momentum is conserved i.e total kinetic energy and momentum before collision is equal to the total kinetic energy and momentum after collision.As kinetic energy is conserved here,so less or ideally no damage occurs to the colliding bodies.

Inelastic collision is that type of collision in which only momentum is conserved but not kinetic energy .After the collision the kinetic energy is lost in forms heat,sound ,light etc.

Normally any deformation and destruction is due to the inelastic collision which results in the loss of kinetic energy.

Hence the helicopters were destroyed and deformed due to inelastic collision.

7 0
2 years ago
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samantha a high school teacher wants to spend more time with her children and is looking for a job in her field. what would be a
sp2606 [1]

She could look for an online job or a job she can work at from home.

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2 years ago
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The charges of two particles are as follows: Q1=2 x 10 -8 C and Q2 = 3 x 10 -7 C. Find the magnitude of the force between these
Fantom [35]

Answer:

F = 3.86 x 10⁻⁶ N

Explanation:

First, we will find the distance between the two particles:

r = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2+(z_{2}-z_{1})^2}\\

where,

r = distance between the particles = ?

(x₁, y₁, z₁) = (2, 5, 1)

(x₂, y₂, z₂) = (3, 2, 3)

Therefore,

r = \sqrt{(3-2)^2+(2-5)^2+(3-1)^2}\\r = 3.741\ m\\

Now, we will calculate the magnitude of the force between the charges by using Coulomb's Law:

F = \frac{kq_{1}q_{2}}{r^2}\\

where,

F = magnitude of force = ?

k = Coulomb's Constant = 9 x 10⁹ Nm²/C²

q₁ = magnitude of first charge = 2 x 10⁻⁸ C

q₂ = magnitude of second charge = 3 x 10⁻⁷ C

r = distance between the charges = 3.741 m

Therefore,

F = \frac{(9\ x\ 10^9\ Nm^2/C^2)(2\ x\ 10^{-8}\ C)(3\ x\ 10^{-7}\ C)}{(3.741\ m)^2}\\

<u>F = 3.86 x 10⁻⁶ N</u>

5 0
2 years ago
A wind instrument that produces only odd-numbered standing wave modes has what configuration of its ends?
Luda [366]

Answer:

Open- closed

Explanation:

It has Open-closed configuration of its end

4 0
2 years ago
If this decay has a half-life of 10.2 years, what mass of 60.8g carbon-14 will remain after 20.4 years
OLEGan [10]
20.4 years is 20.4/10.2 = 2 half-life cycles, which means a quarter of the starting mass or 15.2 g will remain after this time.
5 0
2 years ago
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