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inn [45]
4 years ago
6

If the speed of a wave is 2.5 x 103 m/s and has a wavelength of 5.80 x 10-7m, what is its frequency?

Physics
1 answer:
trasher [3.6K]4 years ago
8 0

Answer:

4.31×10⁹Hz

Explanation:

v=2.5×10³ms⁻¹    wavelength=5.80×10⁻⁷m

v=frequency × wavelength

2.5×10³=f×5.80×10⁻⁷

f=4.31×10⁹Hz

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A model airplane with a mass of 0.741kg is tethered by a wire so that it flies in a circle 30.9 m in radius. The airplane engine
Tju [1.3M]

Answer:

_T}=24.57Nm

ω = 0.0347 rad/s²

a ≅ 1.07 m/s²

Explanation:

Given that:

mass of the model airplane = 0.741 kg

radius of the wire = 30.9 m

Force = 0.795 N

The torque produced by the net thrust about the center of the circle can be calculated as:

_T } = Fr

where;

F represent the magnitude of the thrust

r represent the radius of the wire

Since we have our parameters in set, the next thing to do is to replace it into the above formula;

So;

_T}=(0.795)*(30.9)

_T}=24.57Nm

(b)

Find the angular acceleration of the airplane when it is in level flight rad/s²

_T}=I \omega

where;

I = moment of inertia

ω = angular acceleration

The moment of inertia (I) can also be illustrated as:

I = mr^2

I = ( 0.741) × (30.9)²

I = 0.741 × 954.81

I = 707.51 Kg.m²

_T}=I \omega

Making angular acceleration the subject of the formula; we have;

\omega = \frac{_T}{I}

ω = \frac{24.57}{707.51}

ω = 0.0347 rad/s²

(c)

Find the linear acceleration of the airplane tangent to its flight path.m/s²

the linear acceleration (a) can be given as:

a =  ωr

a = 0.0347 × 30.9

a = 1.07223 m/s²

a ≅ 1.07 m/s²

5 0
3 years ago
Thanks + BRAINLIST <br><br> Please need correct answer asappp
garik1379 [7]
(A) Standing waves are created by two identical waves reflecting off each other

(B) a general definition of a wave interference is, when more than on wave meet and interact in the same medium

Hope this helps :)
3 0
3 years ago
Read 2 more answers
Pam has a mass of 42.4 kg and she is at rest on smooth, level, frictionless ice. Pam straps on a rocket pack. The rocket supplie
fredd [130]

Answer:

F = 2349.6 N

Explanation:

We can solve this exercise using the relationship of momentum and momentum

         I = Δp

         I = F t

As the woman accelerates at a distance of 29.1 m to go from rest to 56.8 m / s, we can use the kinematics to find the acceleration

       v² = v₀² + 2 a x

       v₀ = 0

       a = v / 2x

       a = 56.8 2/2 29.1

       a = 55.43 m / s²

Let's look for the time you need to get this speed

      v = v₀ + a t

      t = v / a

      t = 56.8 / 55.43

      t = 1,025 s

Let's clear the average force momentum from the momentum

      F t = m v- m v₀

      F = mv / t

      F = 42.4 56.8 / 1.025

      F = 2349.6 N

3 0
3 years ago
n a ballistics test, a potato gun shoots a 0.34 kg potato into a 5.0 kg catching cart. The cart recoils at 3.7 m/s after catchin
Gala2k [10]

The initial velocity of the potato is 54.41 m/s.

The given parameters:

  • <em>Mass of the potato, m = 0.34 kg</em>
  • <em>Mass of the cart, m = 5.0 kg </em>
  • <em>Velocity of the recoil, u₂ = 3.7 m/s</em>

<em />

The initial velocity of the potato is calculated by applying the principle of conservation of energy as follows;

m_1u_1 = m_2 u_2\\\\u_1 = \frac{m_2 u_2}{m_1} \\\\u_1 = \frac{5 \times 3.7}{0.34} \\\\u_1 = 54.41 \ m/s

Thus, the initial velocity of the potato is 54.41 m/s.

Learn more about conservation of linear momentum here: brainly.com/question/7538238

6 0
3 years ago
On Earth a ball is thrown straight downward with an initial speed of 1 meter
Montano1993 [528]

-- Gravity adds 9.8 m/s to the downward speed of any object, every second ... as long as there are no other forces messing with it.

-- In 0.6 sec, gravity added (0.6x9.8)= 5.88 m/s to the downward speed of this ball.

-- This ball didn't start from zero. You threw it down with an initial speed of 1 m/s. So after 0.6 sec, with the help of gravity, its speed is

(1) + (5.88) = 6.88 m/s .

Pick choice-C .

Notice that we don't care how high it was off the ground when you threw it, just as long as it was high enough to keep falling for 0.6 sec without hitting the ground.

7 0
4 years ago
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