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2 years ago

What do the magnetic field lines on a bar magnet look like?

Physics

2 answers:

KATRIN_1 [288]2 years ago

6 0

Answer

A is the correct answer

Explanation:

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zubka84 [21]2 years ago

3 0

Answer:

Explanation:

On a bar magnet, the lines start at the north pole and loop around to the south pole. A diagram is attached for any further clarifications.

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Care este legea conservarii sarcinii electrice? ma ajuta cineva?

Black_prince [1.1K]

Answer:

the law of conservation of electric charge that states that electric charge cannot be created or destroyed, it can only be exchanged between bodies.

Explanation:

In physics there are several conservation laws that are of great importance, among them we have the law of conservation of electric charge that states that electric charge cannot be created or destroyed, it can only be exchanged between bodies.

In general, the Earth is a very large body and is considered a reservoir where the electrical charge can be stored, but cannot be destroyed.

6 0

3 years ago

A block is at rest on the incline shown in the figure. The coefficients of static and ki- netic friction are μs = 0.62 and μk =

GREYUIT [131]

The frictional force is 218.6 N

Explanation:

The block in the problem is at rest along the inclined surface: this means that the net force acting along the direction parallel to the incline must be zero.

There are two forces acting along this direction:

- The component of the weight parallel to the incline, downward along the plane, of magnitude

$mg sin \theta$

where

m = 46 kg is the mass

$g=9.8 m/s^2$ is the acceleration of gravity

$\theta=29^{\circ}$ is the angle of the incline

- The (static) frictional force, acting upward, of magnitude $F_f$

Since the block is in equilibrium, we can write

$mg sin \theta - F_f = 0$

And substituting, we find the force of friction:

$F_f = mg sin \theta = (46)(9.8)(sin 29^{\circ})=218.6 N$

Learn more about frictional force along an inclined plane:

brainly.com/question/5884009

#LearnwithBrainly

7 0

3 years ago

A trolley of mass 4 kg moves with a velocity of 0.5 meter per second It colides with a stationary trolley of mass 3 kg. If the t

Luda [366]

Answer:

Approximately $0.29\; {\rm m \cdot s^{-1}}$ .

Explanation:

Make use of the fact that total momentum is conserved in collisions.

The momentum of an object of mass $m$ and velocity $v$ is $p = m\, v$ .

The momentum of the two trolleys before the collision would be:

$4\; {\rm kg} \times 0.5\; {\rm m \cdot s^{-1}} = 2\; {\rm kg \cdot m \cdot s^{-1}}$ .
$3\; {\rm kg} \times 0\; {\rm m\cdot s^{-1}} = 0\; {\rm kg \cdot m \cdot s^{-1}}$ .

Thus, the total momentum of the two trolleys right before the collision would be $2\; {\rm kg \cdot m \cdot s^{-1}}$ .

Since the two trolleys are stuck to one another after the collision, they could modelled as one big trolley of mass $m = 3\; {\rm kg} + 4\; {\rm kg} = 7\; {\rm kg}$ .

The momentum of the two trolleys, combined, is conserved during the collision. Thus, the total momentum of the new trolley of mass $m = 7\; {\rm kg}$ would continue to be $v = 2\; {\rm kg \cdot m \cdot s^{-1}}$ shortly after the collision.