Answer:
Step-by-step explanation:
GIVEN: A farmer has 
of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one side of the pen. The length of the barn is 
.
TO FIND: Determine the dimensions of the rectangle of maximum area that can be enclosed under these conditions.
SOLUTION:
Let the length of rectangle be 
and 
perimeter of rectangular pen 
area of rectangular pen 
putting value of
to maximize 
but the dimensions must be lesser or equal to than that of barn.
therefore maximum length rectangular pen 
width of rectangular pen 
Maximum area of rectangular pen 
Hence maximum area of rectangular pen is 
and dimensions are
Volume of a cube = l^3, where l is the side length (note that the length, width and height in a cube are equal)
Volume of cube = 6^3 = 216 m^3
Answer:
x = 7 and 3/2
Step-by-step explanation:
We can say:
x - 7 = 0 and 2x - 3 = 0
<em>Lets solve for x - 7 = 0 first:</em>
Add 7 to each side of "="
=> <u>x = 7</u>
<em>Now lets solve for 2x - 3 = 0</em>
First add 3 to each side of "="
=> 2x = 3
Now divide each side by 2
<u>=> x = 3/2</u>
Hope this helps!
4x=20-8y
x=5-2y now use this value of x in the second equation...
3(5-2y)+6y=15
15-6y+6y=15
15=15 This is true for any y or x value.
So there are infinitely many solutions as the two equations describe the same line.
26.18 divided by 77 = 0.34. Therefore the percentage change = 66%
