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4 years ago

Does anybody know the answer to this?

Mathematics

2 answers:

labwork [276]4 years ago

8 0

Answer:

D. Pyramid

Step-by-step explanation:

Bogdan [553]4 years ago

7 0

I think the answer is D.

Hope this helps.

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Bonus: Find the measure indicated. *

velikii [3]

Answer:

AC = 16 in.

Step-by-step explanation:

AD = CD = 10 in.

BD = 6 in.

AC = 2(AB) = ?

Apply pythagorean theorem to find AB

AB² = AD² - BD²

Substitute

AB² = 10² - 6²

AB² = 64

AB = √64

AB = 8

Therefore:

AC = 2(AB) = 2(8)

AC = 16 in.

5 0

3 years ago

Help me with the problem plz 6p6

satela [25.4K]

i need more information to answer the question

5 0

3 years ago

Please help I'm not sure what to do first.

nadezda [96]

Answer:

Step-by-step explanation:

it has to be under 90 degrees

7 0

3 years ago

Distrubutive property (m-3)(-10)?

mrs_skeptik [129]

Answer: -10m + 30

Step-by-step explanation:

Given expression

(m - 3) (-10)

Expand parentheses and apply the distributive property

=m · (-10) - 3 · (-10)

Simplify by multiplication

= $\boxed{-10m+30}$

Hope this helps!! :)

Please let me know if you have any questions

4 0

3 years ago

A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num

yKpoI14uk [10]

Answer: hypotenuse = $c^{2} + b^{2}$

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side ( $s_{1},s_{2}$ ) of the right triangle, .i.e.:

$h^{2} = s_{1}^{2} + s_{2}^{2}$

In this question:

$s_{1}$ = $c^{2}-b^{2}$

$s_{2} =$ 2bc

Substituing and taking square root to find hypotenuse:

$h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}$

Calculating:

$h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}$

$h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}$

$c^{4}+b^{4}+2b^{2}c^{2}$ = $(c^{2}+b^{2})^{2}$ , then:

$h=\sqrt{(c^{2}+b^{2})^{2}}$

$h=(c^{2}+b^{2})$

Hypotenuse for the right-angled triangle is $h=(c^{2}+b^{2})$ units

3 0

3 years ago