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denis23 [38]
2 years ago
6

The sum of two integers is 44. The difference of the two integers is 8.

Mathematics
2 answers:
neonofarm [45]2 years ago
8 0

Answer:

18

Step-by-step explanation:

44/2=22

the difference between the two numbers= 8

8/2=4

(22-4) + (22+4) = 18+26 = 44

the smaller number = 18

Umnica [9.8K]2 years ago
6 0

Answer:

The smaller integer is 18.

Step-by-step explanation:

x is the larger integer, and y is the smaller integer.

x + y = 44

x - y = 8

For x - y = 8, add y to both sides and get x = 8 + y.

Change x in x + y = 44 for 8 + y.

8 + y + y = 44

8 + 2y = 44

2y = 36

y = 18

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Using the z-distribution, it is found that the 95% confidence interval for the proportion of all U.S. adults who play video games is (0.4681, 0.5119). It means that we are 95% sure that the true proportion of all U.S. adults who play video games is between 0.4681 and 0.5119.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have that:

  • 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.
  • 49% out of 2001 U.S. adults play video games, hence \pi = 0.49, n = 2001.

The lower bound of the interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.49 - 1.96\sqrt{\frac{0.49(0.51)}{2001}} = 0.4681

The upper bound of the interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.49 + 1.96\sqrt{\frac{0.49(0.51)}{2001}} = 0.5119

The 95% confidence interval for the proportion of all U.S. adults who play video games is (0.4681, 0.5119). It means that we are 95% sure that the true proportion of all U.S. adults who play video games is between 0.4681 and 0.5119.

To learn more about the z-distribution, you can take a look at brainly.com/question/25730047

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