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2 years ago

Use the distributive property to remove the parentheses.

Mathematics

1 answer:

blagie [28]2 years ago

6 0

Answer:

Step-by-step explanation:

10x^2(3x^2 - 5x) Remove the brackets (Distributive Property)

10*3*x^2 * x^2 - 5x * 10x^2

30 x^(2 + 2) - 5*10x^(2+1)

30x^4 - 50x^3

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Twice the length of a rectangle is three times the width. The perimeter of the rectangle is 320 cm. Find the dimensions of the r

alekssr [168]

Answer:

106

Step-by-step explanation:

divided 320 by 3

7 0

3 years ago

Urpi wants to buy towels online. There are two stores with the kind of towel she wants. The first store charges $20 per towel, a

Kamila [148]

Answer:

1 A the first store.

2. B The second store.

Step-by-step explanation:

1. The store with the dearest towel is The First one ( $20 compared with $18).

2. The equation for the cost in the first store is P = 20n + 25.

The cost in the second store is given by P = 18n + 35.

For 15 towels first store charges:

20 * 15 + 25 = $325.

Second store charges:

18 * 15 + 35 = $305.

4 0

3 years ago

Read 2 more answers

22/110 to its lowest terms

Dmitrij [34]

Find the GCF, in this case 11, and divide both the numerator and denominator by it. Here, it turns out to be 2/11 because 22÷11 is 2 and 110÷11 is 11.

3 0

3 years ago

Read 2 more answers

1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

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5 0

3 years ago

Read 2 more answers

Please helpppppp!!!!!!!!

likoan [24]

Answer:

Step-by-step explanation:

6 0

3 years ago