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Mashutka [201]
3 years ago
9

7 identities toys weight 1.4kg how much would 3 toys weigh

Mathematics
2 answers:
Studentka2010 [4]3 years ago
4 0

Answer:

0.6 kg or 600 g

Step-by-step explanation:

If 7 (identical) toys weigh 1.4 kg then 1 toy would weigh 1.4 / 7 = 0.2 kg. Therefore, 3 of those same toys weigh 0.2 * 3 = 0.6 kg or 600 g.

Nimfa-mama [501]3 years ago
3 0

Answer:

0.6 kg

Step-by-step explanation:

→ Work out the weight of one toy

7 toys = 1.4 kg

1 toy = 0.2 kg

→ Multiply both sides by 3

3 toys = 0.6 kg

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Solve the system using elimination. ''x-3y=9 and -x+3y=-9
DiKsa [7]

Answer:

Infinitely many solutions.

Step-by-step explanation:

Let's solve your system by elimination.

x−3y=9;−x+3y=−9

x−3y=9

−x+3y=−9

Add these equations to eliminate x:

0=0

<u>Answer:</u>

Infinitely many solutions.

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2 years ago
How can i solve that equation by factoring
Hoochie [10]

Answer:

y = ( x + 3 )( x + 5 )

Step-by-step explanation:

N/A

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3 years ago
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Jacques needs to convert the function f(x) = x2 − 6x + 14 to vertex form, f(x) = (x − h)2 + k, in order to find the minimum.
Anarel [89]

k = 5

the equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

To obtain this form use the method of completing the square

Since the coefficient of the x² term is 1 then

add/ subtract (half the coefficient of the x-term )² to x² - 6x

f(x) = x² + 2(- 3)x + 9 - 9 + 14 = (x - 3)² + 5 → k = 5


   

5 0
3 years ago
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55% as a fraction in simplest form.
nirvana33 [79]
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3 0
3 years ago
The high school leadership team is having a car wash. They charge $5.50 for large cars and $4.00 for small cars . They had a suc
11Alexandr11 [23.1K]

Answer: 56 large cars and 86 small cars.

Step-by-step explanation:

Let's call:

l: the number of large cars.

s: the number of small cars.

Then, you can set up the following system of equations:

\left \{ {{l+s=142} \atop {5.50l+4.0s=652.50}} \right.

You can use the Elimination Method:

- Multiply the first equation by -4.0

- Add both equations.

- Solve for l.

\left \{ {{-4.0l-4.0s=-568} \atop {5.50l+4.0s=652.50}} \right.\\--------\\1.5l=84.5

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Substitute l=56 into one of the original equations and solve for <em>s:</em>

<em> </em>56+s=142\\s=142-56\\s=86

3 0
2 years ago
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