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katen-ka-za [31]
3 years ago
6

The vertices of ∆CDE are C(–3, 3), D(4, 9), and E(6, 1). Translateusing ∆CDE vector (5,-3)

Mathematics
1 answer:
VLD [36.1K]3 years ago
8 0

Answer:

The answer is D(4, 9)

Step-by-step explanation:

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AB = -10

Im confused is this what you wanted?

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If it is 3;50 and i have to leave at 4;45 how long do i have
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3 pound of apples for $4.59.
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8 0
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A 90 percent confidence interval is to be created to estimate the proportion of television viewers in a certain area who favor m
Dominik [7]

Answer:

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The width of the interval is:

W = 2z\sqrt{\frac{\pi(1-\pi)}{n}}

In this sample:

Two 90% intervals, with different lenghts. So both have the same values for z an \pi

Interval A:

9000 viewers.

So the width is

W_{A} = 2z\sqrt{\frac{\pi(1-\pi)}{9000}}

Interval B:

100 viewers

So the width is

W_{B} = 2z\sqrt{\frac{\pi(1-\pi)}{1000}}

Relationship between the widths:

R = \frac{W_{A}}{W_{B}} = \frac{2z\sqrt{\frac{\pi(1-\pi)}{9000}}}{2z\sqrt{\frac{\pi(1-\pi)}{1000}}} = \frac{\sqrt{1000}}{\sqrt{9000}} = \frac{\sqrt{1}}{\sqrt{9}} = \frac{1}{3}

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

8 0
4 years ago
Help please !!!!!!!!!!!
yuradex [85]
I think the answer is D.
6 0
4 years ago
Read 2 more answers
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