By definition, we have to:
Where,
F: force [N]
m: mass of the object [Kg]
a: acceleration of the object [m / s ^ 2]
Clearing the acceleration we have:
Substituting values we have:
Rounding the nearest whole we have:
Answer:
the acceleration of the ball is:
solution:
1.6 m/s = 96 m/min (in other words, 1.6 m/s x 60 s/min)
96 m/min x 8.3 min = 796.8 m
Answer:
What was your hypothesis? According to your data, do you think your hypothesis was correct? (Be sure to refer to your data when answering this question.)
Summarize any difficulties or problems you had in performing the experiment that might have affected the results. Describe how you might change the procedure to avoid these problems.
Be sure to submit your data along with your paragraph.
Part 2
What effect did the temperature have on the viscosity of the honey? (Be sure to refer to your data when answering this question.)
Give at least two practical examples where knowledge of viscosity is important.
Essay Question:
Write a summary paragraph for each part discussing this experiment and the results. Use the following questions and topics to help guide the content of your paragraph.
Part 1
What was your hypothesis? According to your data, do you think your hypothesis was correct? (Be sure to refer to your data when answering this question.)
Summarize any difficulties or problems you had in performing the experiment that might have affected the results. Describe how you might change the procedure to avoid these problems.
Be sure to submit your data along with your paragraph.
Part 2
What effect did the temperature have on the viscosity of the honey? (Be sure to refer to your data when answering this question.)
Give at least two practical examples where knowledge of viscosity is important.
Uh I don’t know why their is so Many questions and I try answering every single one
Answer: 0.213m
Explanation: The fundamental frequency is 805Hz.
The second harmonic (first overtone ) is 1035 Hz and the third harmonic (second overtone) is 1265 Hz.
The pipe is an air filled hence it is a closed pipe
Recall that v = f λ
At fundamental frequency
Where v = speed of sound in air (v) = 343 m/s
Fundamental frequency (f) = 805 Hz
Wavelength ( λ) = ?
By substituting the parameters, we have that
343 = 805 × λ
λ = 343 / 805
λ = 0.426m
The pipe is an open one and at the fundamental frequency, hence the relationship between wavelength ( λ) and length of air is given as
L = λ/4
But λ = 0.426m
L = 0.426/2
L = 0.213m
