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Dima020 [189]
4 years ago
8

Write a summary paragraph of 200 words discussing this experiment and the results. Use the following questions and topics to hel

p guide the content of your paragraph.
Summarize your results.
According to your data, was your hypothesis correct? (Be sure to refer to your data when answering this question.) If the hypothesis was not correct, what do the results of the lab indicate the correct answer is?
Summarize any difficulties or problems you had in performing the experiment that might have affected the results. Describe how you might change the procedure to avoid these problems.
Describe how the results might be applied in the real world.
Physics
1 answer:
Papessa [141]4 years ago
5 0

Answer:

What was your hypothesis? According to your data, do you think your hypothesis was correct? (Be sure to refer to your data when answering this question.)

Summarize any difficulties or problems you had in performing the experiment that might have affected the results. Describe how you might change the procedure to avoid these problems.

Be sure to submit your data along with your paragraph.

Part 2

What effect did the temperature have on the viscosity of the honey? (Be sure to refer to your data when answering this question.)

Give at least two practical examples where knowledge of viscosity is important.

Essay Question:

Write a summary paragraph for each part discussing this experiment and the results. Use the following questions and topics to help guide the content of your paragraph.

Part 1

What was your hypothesis? According to your data, do you think your hypothesis was correct? (Be sure to refer to your data when answering this question.)

Summarize any difficulties or problems you had in performing the experiment that might have affected the results. Describe how you might change the procedure to avoid these problems.

Be sure to submit your data along with your paragraph.

Part 2

What effect did the temperature have on the viscosity of the honey? (Be sure to refer to your data when answering this question.)

Give at least two practical examples where knowledge of viscosity is important.

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A force off 700 newtons is applied to a 600 kg bowling ball. What is the acceleration of the bowling ball once the force is appl
Readme [11.4K]

Answer:

<h2>1.17 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{700}{600}  =  \frac{7}{6}  \\  = 1.1666666...

We have the final answer as

<h3>1.17 m/s²</h3>

Hope this helps you

6 0
3 years ago
Since the Wagon is being pulled down hill is it increasing (C)
Ket [755]
<em>Since the wagon is being pulled down hill with a constant velocity, all the forces of the wagon would be (C) increasing.</em>
<em>You are correct! **</em>
4 0
3 years ago
A mass m is attached to an ideal massless spring with spring constant k. In experiment 1 the mass oscillates with amplitude a, a
Trava [24]

Time period remains the same in both the experiment as change in amplitude does not affect time period.

What are the factors on which time period depends in SHM?

Time period is given by:

T=2\pi \sqrt{\frac{m}{k} }

where,

T = time period

m = mass

k = spring constant

In a straightforward harmonic motion, we see from the preceding formula that the time period depends only on the object's mass and spring constant (SHM). The time period will adjust to any variations in the object's mass or the spring constant.

What is Spring Constant?

A spring's "spring constant" is a property that quantifies the relationship between the force acting on the spring and the displacement it produces. In other words, it characterises a spring's stiffness and the extent of its range of motion.

Learn more about SHM here:

brainly.com/question/20885248

#SPJ4

6 0
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4 0
3 years ago
Read 2 more answers
An 82 kg jogger has 810 J of kinetic energy. What is the jogger’s velocity?
yan [13]
By definition, the kinetic energy is given by:
 k = (1/2) * (m) * (v ^ 2)&#10;
 Where,
 m: mass
 v: speed
 Clearing the speed we have:
 v ^ 2 = (2 * k) / m&#10;&#10; v =  \sqrt{(2 * k) / m}
 Substituting values:
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 Answer:
 
The jogger's velocity is:
 
v = 4.44 m / s
3 0
3 years ago
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