Answer:
Halogen Family of elements
Explanation:
Group Seventeen
<span>54.8 g of MgI2 can be produced.
To solve this, you need to determine the molar mass of each reactant and the product. First, look up the atomic weights of iodine and magnesium
Atomic weight of Iodine = 126.90447
Atomic weight of Magnesium = 24.305
Molar mass of MgI2 = 24.305 + 2 * 126.90447 = 278.11394
Now determine how many moles of Iodine and Magnesium you have
moles of Iodine = 50.0 g / 126.90447 g/mol = 0.393997154 mole
moles of Magnesium = 5.15 / 24.305 g/mol = 0.211890557 mole
Since for every magnesium atom, you need 2 iodine atoms and since the number of moles of available iodine isn't at least 2 times the available moles of magnesium, iodine is the limiting reagent.
So figure out how many moles of magnesium will be consumed by the iodine
0.393997154 mole / 2 = 0.196998577 mole.
This means that you can make 0.196998577 moles of MgI2. Now simply multiply by the previously calculated molar mass of MgI2
0.196998577 mole * 278.11394 g/mole = 54.78805 g
Round the result to the correct number of significant figures.
54.78805 g = 54.8 g</span>
1) Conversion of an isotope one chemical element or an isotope into another chemical element is called as nuclear transmutation.
<span>
2) In a nuclear transmutation reactions</span> can be achieved either due to radioactive decay or due to nuclear reactions.
3) In this technique, it is possible to convert a stable element into radioactive atom by bombarding in with high speed particles. The initial stable nuclei is referred as parent nuclei, the fast moving particle is referred as projectile while new element which is formed is called as daughter element.
4) In the present reaction:
<span>1 1 H+ 1 0 n -> 2 1 H
1 1H is a parent nuclei which is bombarded with the fast moving projectile
(1 0 n) to generate a new daughter nuclei (2 1H). </span>
